document.write( "Question 200966This question is from textbook
\n" ); document.write( ": log2x-log9x-2=1 A:2.431\r
\n" ); document.write( "\n" ); document.write( "log5(z-3)=2 A: z=28\r
\n" ); document.write( "\n" ); document.write( "can you please give me step by step in solving these problem
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Algebra.Com's Answer #151194 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
log2x-log9x-2=1 A:2.431
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\n" ); document.write( "Comment:
\n" ); document.write( "log2x-log9x = log[2x/9x] = log[2/9)
\n" ); document.write( "That leaves no variable in the equation.
\n" ); document.write( "So what do you mean by log2x and log 9x???
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\n" ); document.write( "log5(z-3)=2 A: z=28
\n" ); document.write( "I assume you mean 5 to be the base:
\n" ); document.write( "z-3 = 5^2
\n" ); document.write( "z = 25+3
\n" ); document.write( "z = 28
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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