document.write( "Question 200682: The accountant department at Weston Materials, inc, a national manufacturer of unattached garages, reports that it takes two construction workers a mean of 32 hours and a standard deviation of 2 hours to erect the Red Barn model Assume the assemble times follow the normal distribution.\r
\n" ); document.write( "\n" ); document.write( "a) Determine the z values for 29 and 34 hours. What percent of the garage takes between 32 and 34 hours to erect?
\n" ); document.write( "b) What percent of the garage take between 29 hours and 34 hours to erect
\n" ); document.write( "c) What percent of the garage takes between 28.7 hours or less erect?
\n" ); document.write( "d) Of the garage, 5 percent take how mant hours or more to erect
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Algebra.Com's Answer #151191 by stanbon(75887)\"\" \"About 
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The accountant department at Weston Materials, inc, a national manufacturer of unattached garages, reports that it takes two construction workers a mean of 32 hours and a standard deviation of 2 hours to erect the Red Barn model Assume the assemble times follow the normal distribution.
\n" ); document.write( "a) Determine the z values for 29 and 34 hours. What percent of the garage takes between 32 and 34 hours to erect?
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\n" ); document.write( "z(29) = (29-32)/2 = -3/2 = -1.5
\n" ); document.write( "z(34) = (34-32)/2 = 2/2 = 1
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\n" ); document.write( "b) What percent of the garage take between 29 hours and 34 hours to erect
\n" ); document.write( "P(29\n" ); document.write( "------------------------------------------------------
\n" ); document.write( "c) What percent of the garage takes between 28.7 hours or less erect?
\n" ); document.write( "Find the z-values of 28.7 and 0.
\n" ); document.write( "Then find the percentage between those two z values to get:
\n" ); document.write( "Ans: 4.95%
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\n" ); document.write( "d) Of the garage, 5 percent take how many hours or more to erect
\n" ); document.write( "The z value of 5% is -1.645
\n" ); document.write( "Find the x-value corresponding to z=-1.645
\n" ); document.write( "x = zs+u
\n" ); document.write( "x = -1.645*2 + 32
\n" ); document.write( "x = 28.71 hrs.
\n" ); document.write( "Ans: # of hours >= 28.71
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.\r
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