document.write( "Question 200938: This is 5 different problems I've been having problems with for a while.\r
\n" ); document.write( "\n" ); document.write( "4/sqrt5
\n" ); document.write( "4sqrtx^12/24sqrtx^12
\n" ); document.write( "15sqrt8x^16/5sqrt2x^4
\n" ); document.write( "(3sqrt5)(2sqrt10)
\n" ); document.write( "(2sqrtx)(5sqrtx^3)
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Algebra.Com's Answer #151157 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
I'll do the first three to get you going in the right direction.\r
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\n" ); document.write( "\n" ); document.write( "\"4%2Fsqrt%285%29\" Start with the given expression.\r
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\n" ); document.write( "\n" ); document.write( "\"%284%2Asqrt%285%29%29%2F%28sqrt%285%29%2Asqrt%285%29%29\" Multiply both the numerator and denominator by \"sqrt%285%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"%284%2Asqrt%285%29%29%2F%28sqrt%285%2A5%29%29\" Combine the roots.\r
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\n" ); document.write( "\n" ); document.write( "\"%284%2Asqrt%285%29%29%2F%28sqrt%2825%29%29\" Multiply\r
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\n" ); document.write( "\n" ); document.write( "\"%284%2Asqrt%285%29%29%2F5\" Take the square root of 25 to get 5\r
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\n" ); document.write( "\n" ); document.write( "So \"4%2Fsqrt%285%29=%284%2Asqrt%285%29%29%2F5\"\r
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\n" ); document.write( "\n" ); document.write( "\"%284%2Asqrt%28x%5E12%29%29%2F%2824%2Asqrt%28x%5E12%29%29\" Start with the given expression.\r
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\n" ); document.write( "\n" ); document.write( "\"%284%2Asqrt%28x%5E12%29%29%2F%284%2A6%2Asqrt%28x%5E12%29%29\" Factor 24 to get 4*6\r
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\n" ); document.write( "\n" ); document.write( "\"%28cross%284%29%2Asqrt%28x%5E12%29%29%2F%28cross%284%29%2A6%2Asqrt%28x%5E12%29%29\" Cancel out the common terms.\r
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\n" ); document.write( "\n" ); document.write( "\"%28sqrt%28x%5E12%29%29%2F%286%2Asqrt%28x%5E12%29%29\" Simplify\r
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\n" ); document.write( "\n" ); document.write( "\"sqrt%28%28x%5E12%29%2F%28x%5E12%29%29%2F%286%29\" Combine the roots\r
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\n" ); document.write( "\n" ); document.write( "\"sqrt%281%29%2F6\" Divide\r
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\n" ); document.write( "\n" ); document.write( "\"1%2F6\" Simplify\r
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\n" ); document.write( "\n" ); document.write( "So \"%284%2Asqrt%28x%5E12%29%29%2F%2824%2Asqrt%28x%5E12%29%29=1%2F6\" where \"x%3E0\"\r
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\n" ); document.write( "\n" ); document.write( "\"%2815%2Asqrt%288x%5E16%29%29%2F%285%2Asqrt%282x%5E4%29%29\" Start with the given expression.\r
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\n" ); document.write( "\n" ); document.write( "\"%285%2A3%2Asqrt%288x%5E16%29%29%2F%285%2Asqrt%282x%5E4%29%29\" Factor 15 into 5*3\r
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\n" ); document.write( "\n" ); document.write( "\"%28cross%285%29%2A3%2Asqrt%288x%5E16%29%29%2F%28cross%285%29%2Asqrt%282x%5E4%29%29\" Cancel out the common terms.\r
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\n" ); document.write( "\n" ); document.write( "\"%283%2Asqrt%288x%5E16%29%29%2F%28sqrt%282x%5E4%29%29\" Simplify\r
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\n" ); document.write( "\n" ); document.write( "\"3%2Asqrt%28%288x%5E16%29%2F%282x%5E4%29%29\" Combine the roots.\r
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\n" ); document.write( "\n" ); document.write( "\"3%2Asqrt%28%284%2A2x%5E16%29%2F%282x%5E4%29%29\" Factor 8 into 4*2\r
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\n" ); document.write( "\n" ); document.write( "\"3%2Asqrt%28%284%2Across%282%29x%5E16%29%2F%28cross%282%29x%5E4%29%29\" Cancel out the common terms.\r
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\n" ); document.write( "\n" ); document.write( "\"3%2Asqrt%28%284x%5E16%29%2F%28x%5E4%29%29\" Simplify\r
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\n" ); document.write( "\n" ); document.write( "\"3%2Asqrt%284x%5E%2816-4%29%29\" Divide the variable terms by subtracting the exponents.\r
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\n" ); document.write( "\n" ); document.write( "\"3%2Asqrt%284x%5E12%29\" Subtract\r
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\n" ); document.write( "\n" ); document.write( "\"3%2Asqrt%284%2Ax%5E2%2Ax%5E2%2Ax%5E2%2Ax%5E2%2Ax%5E2%2Ax%5E2%29\" Factor \"x%5E12\" into \"x%5E2%2Ax%5E2%2Ax%5E2%2Ax%5E2%2Ax%5E2%2Ax%5E2\" note: there are 6 \"x%5E2\" terms.\r
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\n" ); document.write( "\n" ); document.write( " Break up the square root using the identity \"sqrt%28A%2AB%29=sqrt%28A%29%2Asqrt%28B%29\".\r
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\n" ); document.write( "\n" ); document.write( " Take the square root of \"4\" to get \"2\".\r
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\n" ); document.write( "\n" ); document.write( "\"3%2A2%2Ax%2Ax%2Ax%2Ax%2Ax%2Ax\" Take the square root of \"x%5E2\" to get \"x\".\r
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\n" ); document.write( "\n" ); document.write( "\"6x%5E6\" Multiply.\r
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\n" ); document.write( "\n" ); document.write( "Answer:\r
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\n" ); document.write( "\n" ); document.write( "So \"%2815%2Asqrt%288x%5E16%29%29%2F%285%2Asqrt%282x%5E4%29%29\" simplifies to \"6x%5E6\"\r
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\n" ); document.write( "\n" ); document.write( "In other words, \"%2815%2Asqrt%288x%5E16%29%29%2F%285%2Asqrt%282x%5E4%29%29=6x%5E6\" where \"x%3E0\"\r
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\n" ); document.write( "\n" ); document.write( "Edit: The other poster is correct in saying that \"x\" doesn't need to be non-negative, BUT recall that \"sqrt%28x%5E2%29=abs%28x%29\". If we assume that \"x%3E=0\" (ie it is NOT negative), then \"sqrt%28x%5E2%29=x\" which simplifies things greatly. If \"x\" can be any number, then you must include the absolute value.
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