document.write( "Question 27724: Can someone help?
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\n" ); document.write( "\n" ); document.write( "When using the quadratic formula to solve a quadratic equation ax2 + bx + c = 0, the discriminant is b2 - 4ac. This discriminant can be positive, zero, or negative. (When the discriminate is negative, then we have the square root of a negative number. This is called an imaginary number, sqrt(-1) = i. )\r
\n" ); document.write( "\n" ); document.write( "•Explain what the value of the discriminant means to the graph of y = ax2 + bx + c. Hint: Chose values of a, b and c to create a particular discriminant. Then, graph the corresponding equation.
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Algebra.Com's Answer #15113 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
Let a=1,b=1,c=1
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Solved by pluggable solver: SOLVE quadratic equation with variable
Quadratic equation \"ax%5E2%2Bbx%2Bc=0\" (in our case \"1x%5E2%2B1x%2B1+=+0\") has the following solutons:
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\n" ); document.write( " \"x%5B12%5D+=+%28b%2B-sqrt%28+b%5E2-4ac+%29%29%2F2%5Ca\"
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\n" ); document.write( " For these solutions to exist, the discriminant \"b%5E2-4ac\" should not be a negative number.
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\n" ); document.write( " First, we need to compute the discriminant \"b%5E2-4ac\": \"b%5E2-4ac=%281%29%5E2-4%2A1%2A1=-3\".
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\n" ); document.write( " The discriminant -3 is less than zero. That means that there are no solutions among real numbers.

\n" ); document.write( " If you are a student of advanced school algebra and are aware about imaginary numbers, read on.

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\n" ); document.write( " In the field of imaginary numbers, the square root of -3 is + or - \"sqrt%28+3%29+=+1.73205080756888\".
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\n" ); document.write( " The solution is
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\n" ); document.write( " Here's your graph:
\n" ); document.write( "\"graph%28+500%2C+500%2C+-10%2C+10%2C+-20%2C+20%2C+1%2Ax%5E2%2B1%2Ax%2B1+%29\"

\n" ); document.write( "\n" ); document.write( "b^2-4ac=1-4=-3
\n" ); document.write( "This means the roots (zero's) will be imaginary.
\n" ); document.write( "Notice that the graph does not intersect the \"x-axis\".
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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