document.write( "Question 200873: Half the supplement of an angle is 12 degrees less than twice the complement of the angle. Find the measure of the angle. \n" ); document.write( "
Algebra.Com's Answer #151121 by ankor@dixie-net.com(22740)\"\" \"About 
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Half the supplement of an angle is 12 degrees less than twice the complement of the angle.
\n" ); document.write( "Find the measure of the angle.
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\n" ); document.write( "Let the angle be x:
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\n" ); document.write( "Write a equation for the statement:
\n" ); document.write( "\"Half the supplement of an angle is 12 degrees less than twice the complement of the angle.\"
\n" ); document.write( "\"1%2F2\"(180-x) = 2(90-x) - 12
\n" ); document.write( "Multiply both sides by 2 to get rid of the fraction, results:
\n" ); document.write( "180 - x = 4(90-x) - 24
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\n" ); document.write( "180 - x = 360 - 4x - 24
\n" ); document.write( "-x + 4x = 360 - 24 - 180
\n" ); document.write( "3x = 156
\n" ); document.write( "x = \"156%2F3\"
\n" ); document.write( "x = 52 degrees is the angle
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\n" ); document.write( "Check solution in the original equation:
\n" ); document.write( "\"1%2F2\"(180-52) = 2(90-52) - 12
\n" ); document.write( "\"1%2F2\"(128) = 2(38) - 12
\n" ); document.write( "64 = 76 - 12
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