document.write( "Question 200818: The moving sidewalk at Chicago's airport moves 1.8 ft/sec. Walking on the moving sidewalk, Joe travels 105 ft forward in the time it takes to travel 51 ft. in the opposite direction. How fast would Joe be walking on a nonmoving sidewalk? \n" ); document.write( "
Algebra.Com's Answer #151092 by ankor@dixie-net.com(22740)\"\" \"About 
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The moving sidewalk at Chicago's airport moves 1.8 ft/sec.
\n" ); document.write( " Walking on the moving sidewalk, Joe travels 105 ft forward in the time it takes
\n" ); document.write( " to travel 51 ft. in the opposite direction.
\n" ); document.write( " How fast would Joe be walking on a non-moving sidewalk?
\n" ); document.write( ":
\n" ); document.write( "Let s = speed on a non-moving sidewalk
\n" ); document.write( ":
\n" ); document.write( "(s+1.8) = speed moving with it
\n" ); document.write( "(s-1.8) = speed moving against it
\n" ); document.write( ":
\n" ); document.write( "Write a time equation: Time = dist/speed
\n" ); document.write( ":
\n" ); document.write( "\"105%2F%28%28s%2B1.8%29%29\" = \"51%2F%28%28s-1.8%29%29\"
\n" ); document.write( "Cross multiply
\n" ); document.write( "105(s-1.8) = 51(s+1.8)
\n" ); document.write( "105s - 189 = 51s + 91.8
\n" ); document.write( "105s - 51s = 91.8 + 189
\n" ); document.write( "54s = 280.8
\n" ); document.write( "s = \"280.8%2F54\"
\n" ); document.write( "s = 5.2 ft/sec on an ordinary sidewalk
\n" ); document.write( ":
\n" ); document.write( ":
\n" ); document.write( "Check solution by find that the times are equal
\n" ); document.write( "105/(5.2+1.8) = 15 sec
\n" ); document.write( "51/(5.2-1.8) = 15 sec \n" ); document.write( "
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