document.write( "Question 200854: The Jurassic Zoo charges $28.00 for each adult admission and $12.00 for each child. The total bill for 254 people from a school trip was $3864.00. How many adults and how many children went to the zoo? \n" ); document.write( "
Algebra.Com's Answer #151082 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
Let \r
\n" ); document.write( "\n" ); document.write( "a = # of adults that attended
\n" ); document.write( "c = # of children that attended\r
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\n" ); document.write( "\n" ); document.write( "Since a total of 254 people attended, this means that \"a%2Bc=254\". Also, because \"The Jurassic Zoo charges $28.00 for each adult admission and $12.00 for each child\" and \"The total bill for 254 people from a school trip was $3864.00\", we know that \"28a%2B12c=3864\"\r
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\n" ); document.write( "\n" ); document.write( "So we have the system of equations:\r
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\n" ); document.write( "\n" ); document.write( "\"system%28a%2Bc=254%2C28a%2B12c=3864%29\"\r
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\n" ); document.write( "\n" ); document.write( "In order to solve for one variable, we must eliminate the other variable. So if we wanted to solve for \"a\", we would have to eliminate \"c\" (or vice versa).\r
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\n" ); document.write( "\n" ); document.write( "So lets eliminate \"c\". In order to do that, we need to have both \"c\" coefficients that are equal but have opposite signs (for instance 2 and -2 are equal but have opposite signs). This way they will add to zero and cancel out.\r
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\n" ); document.write( "\n" ); document.write( "So to make the \"c\" coefficients equal but opposite, we need to multiply both \"c\" coefficients by some number to get them to an equal number. So if we wanted to get 1 and 12 to some equal number, we could try to get them to the LCM 12. However, we want one number equal to 12 and the other equal to -12. \r
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\n" ); document.write( "\n" ); document.write( "Because one \"c\" coefficient is already equal to 12, we need to multiply both sides of the first equation by -12 (to get the \"c\" coefficient equal to -12).\r
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\n" ); document.write( "\n" ); document.write( "\"28a%2B12c=3864\" Start with the first equation.\r
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\n" ); document.write( "\n" ); document.write( "\"-12%28a%2Bc%29=-12%28254%29\" Multiply the both sides of the first equation by -12.\r
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\n" ); document.write( "\n" ); document.write( "\"-12a-12c=-3048\" Distribute and multiply.\r
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\n" ); document.write( "\n" ); document.write( "So we have the new system of equations:\r
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\n" ); document.write( "\n" ); document.write( "\"system%28-12a-12c=-3048%2C28a%2B12c=3864%29\"\r
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\n" ); document.write( "\n" ); document.write( "Take note that the \"c\" coefficients are equal but opposite.\r
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\n" ); document.write( "\n" ); document.write( "Now add the equations together. You can do this by simply adding the two left sides and the two right sides separately like this:\r
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\n" ); document.write( "\n" ); document.write( "\"%28-12a-12c%29%2B%2828a%2B12c%29=%28-3048%29%2B%283864%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"%28-12a%2B28a%29%2B%28-12c%2B12c%29=-3048%2B3864\" Group like terms.\r
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\n" ); document.write( "\n" ); document.write( "\"16a%2B0c=816\" Combine like terms.\r
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\n" ); document.write( "\n" ); document.write( "\"16a=816\" Simplify.\r
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\n" ); document.write( "\n" ); document.write( "\"a=%28816%29%2F%2816%29\" Divide both sides by \"16\" to isolate \"a\".\r
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\n" ); document.write( "\n" ); document.write( "\"a=51\" Reduce.\r
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\n" ); document.write( "\n" ); document.write( "\"-12a-12c=-3048\" Now go back to the first equation.\r
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\n" ); document.write( "\n" ); document.write( "\"-12%2851%29-12c=-3048\" Plug in \"a=51\".\r
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\n" ); document.write( "\n" ); document.write( "\"-612-12c=-3048\" Multiply.\r
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\n" ); document.write( "\n" ); document.write( "\"-12c=-3048%2B612\" Add \"612\" to both sides.\r
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\n" ); document.write( "\n" ); document.write( "\"-12c=-2436\" Combine like terms on the right side.\r
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\n" ); document.write( "\n" ); document.write( "\"c=%28-2436%29%2F%28-12%29\" Divide both sides by \"-12\" to isolate \"c\".\r
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\n" ); document.write( "\n" ); document.write( "\"c=203\" Reduce.\r
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\n" ); document.write( "\n" ); document.write( "Answer:\r
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\n" ); document.write( "\n" ); document.write( "So the solutions are \"a=51\" and \"c=203\".\r
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\n" ); document.write( "\n" ); document.write( "This means that 51 adults attended and 203 children attended.\r
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