document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=200831>Question 200831</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the binomial factors for the following trinomial and check using the FOIL method.\r<BR>\n" );
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document.write( "9y^2-12y+4 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #151081 by </B><A HREF=/tutors/aboutme.mpl?userid=RAY100><B>RAY100(1637)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=RAY100><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=151081\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 9y^2 -12y +4,,,,,,,,,factors  of  9(9-1, 3-3)  factors  of  4(4-1, 2-2),,, (+) third  term  means  signs  are  the  same,  and  factor  multiples  add,,,,(-) 2nd  term  means,  signs  are (-).<BR>\n" );
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document.write( "( 3y-2) (3y-2)<BR>\n" );
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document.write( "F = 3y*3y= 9y^2<BR>\n" );
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document.write( "O= 3y*-2 = -6y<BR>\n" );
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document.write( "I = 3y *-2 = -6y<BR>\n" );
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document.write( "L = -2*-2 = +4<BR>\n" );
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document.write( "combining  middle  terms  ,,,  9y^2 -12y +4 <BR>\n" );
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