document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=200833>Question 200833</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the binomial factors for the following trinomial and check using the FOIL method.\r<BR>\n" );
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document.write( "4n^2-5n-6 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #151079 by </B><A HREF=/tutors/aboutme.mpl?userid=RAY100><B>RAY100(1637)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=RAY100><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=151079\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 4n^2 -5n -6,,,,,factors  of  4( 4*1, 2*2),, factors  of 6 (6*1,,3*2),,,last  term  (-)  means  difference  of  <BR>\n" );
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document.write( "middle  terms,  or  factors,,,,  2nd  term  (-) means  largest  factor  multiple  is  (-)<BR>\n" );
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document.write( "(4n+3)(n-2)<BR>\n" );
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document.write( "F = 4n *n = 4n^2<BR>\n" );
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document.write( "O = 4n * -2 =-8n<BR>\n" );
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document.write( "I = n*3 =3n<BR>\n" );
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document.write( "L = 3*-2 = -6<BR>\n" );
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document.write( "combining  middle  terms  ,,,,4n^2 -5n -6 </SPAN>\n" );
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