document.write( "Question 200850: If 4a+3b=27 and 3a+4b=29, then 7a+7b/2=? \n" ); document.write( "
Algebra.Com's Answer #151075 by RAY100(1637)\"\" \"About 
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(1) 4a +3b =27
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\n" ); document.write( "multiply (1) by 3,,,,and (2) by 4
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\n" ); document.write( "(3) 12a +9b = 81
\n" ); document.write( "(4) 12a +16b = 116
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\n" ); document.write( "(4) - (3)
\n" ); document.write( "7b = 35
\n" ); document.write( "b=5
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\n" ); document.write( "subst into (1)
\n" ); document.write( "4a +3(5) = 27
\n" ); document.write( "4a =12
\n" ); document.write( "a=3
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\n" ); document.write( "(1) 4(3) +3(5) = 27,,,,,12 +15 =27 ,,,,,,ok
\n" ); document.write( "(2) 3(3) +4(5) =29,,,,9+20=29,,,,,,,ok
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\n" ); document.write( "subst into 7a + 7b/2 = 7(3) +7(5) /2 = 21 + 35/2 = 38.5
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\n" ); document.write( "or subst (7a +7b )/2 = (7*3 +7*5)/2= 56 /2 =28
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