document.write( "Question 200817: It takes Steve 3 hrs longer to paint a floor than it takes Paul. When working together, it takes them 2 hours. How long would each take to do the job alone? \n" ); document.write( "
Algebra.Com's Answer #151057 by nerdybill(7384)![]() ![]() You can put this solution on YOUR website! It takes Steve 3 hrs longer to paint a floor than it takes Paul. When working together, it takes them 2 hours. How long would each take to do the job alone? \n" ); document.write( ". \n" ); document.write( "Let p = time it takes for Paul to paint the floor alone \n" ); document.write( "then \n" ); document.write( "p+3 = time it takes for Steve to paint the floor alone \n" ); document.write( ". \n" ); document.write( "2(1/p + 1/(p+3)) = 1 \n" ); document.write( "2/p + 2/(p+3) = 1 \n" ); document.write( "2(p+3) + 2p = p(p+3) \n" ); document.write( "2p+ 6 + 2p = p^2+3p \n" ); document.write( "8p+ 6 = p^2+3p \n" ); document.write( "6 = p^2-5p \n" ); document.write( "0 = p^2-5p-6 \n" ); document.write( "0 = (p-6)(p+1) \n" ); document.write( "p = {6, -1} \n" ); document.write( "We throw out the negative solution leaving us with: \n" ); document.write( "p = 6 hours (time it takes Paul) \n" ); document.write( ". \n" ); document.write( "Steve: \n" ); document.write( "p+3 = 6+3 = 9 hours (time it takes Steve)\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |