document.write( "Question 200813: get the value of x and y
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document.write( "x-y=5
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document.write( "3x+y=3 \n" );
document.write( "
Algebra.Com's Answer #151054 by nerdybill(7384)![]() ![]() You can put this solution on YOUR website! Applying the substitution method: \n" ); document.write( "x-y=5 (equation 1) \n" ); document.write( "3x+y=3 (equation 2) \n" ); document.write( ". \n" ); document.write( "Solve equation 1 for x: \n" ); document.write( "x-y=5 \n" ); document.write( "x = y+5 \n" ); document.write( "Substitute the above into equation 2 and solve for y: \n" ); document.write( "3x+y=3 \n" ); document.write( "3(y+5)+y=3 \n" ); document.write( "3y+15+y=3 \n" ); document.write( "4y+15=3 \n" ); document.write( "4y = -12 \n" ); document.write( "y = -3 \n" ); document.write( ". \n" ); document.write( "Substitute the above into equation 1 and solve for x: \n" ); document.write( "x-y=5 \n" ); document.write( "x-(-3)=5 \n" ); document.write( "x+3 = 5 \n" ); document.write( "x = 2 \n" ); document.write( ". \n" ); document.write( "Solution: \n" ); document.write( "x=2 and y=-3 \n" ); document.write( " \n" ); document.write( " |