document.write( "Question 200813: get the value of x and y
\n" ); document.write( "x-y=5
\n" ); document.write( "3x+y=3
\n" ); document.write( "

Algebra.Com's Answer #151054 by nerdybill(7384)\"\" \"About 
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Applying the substitution method:
\n" ); document.write( "x-y=5 (equation 1)
\n" ); document.write( "3x+y=3 (equation 2)
\n" ); document.write( ".
\n" ); document.write( "Solve equation 1 for x:
\n" ); document.write( "x-y=5
\n" ); document.write( "x = y+5
\n" ); document.write( "Substitute the above into equation 2 and solve for y:
\n" ); document.write( "3x+y=3
\n" ); document.write( "3(y+5)+y=3
\n" ); document.write( "3y+15+y=3
\n" ); document.write( "4y+15=3
\n" ); document.write( "4y = -12
\n" ); document.write( "y = -3
\n" ); document.write( ".
\n" ); document.write( "Substitute the above into equation 1 and solve for x:
\n" ); document.write( "x-y=5
\n" ); document.write( "x-(-3)=5
\n" ); document.write( "x+3 = 5
\n" ); document.write( "x = 2
\n" ); document.write( ".
\n" ); document.write( "Solution:
\n" ); document.write( "x=2 and y=-3
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