document.write( "Question 200801: give an ordered pair (x,y) of numbers that satisfy the equation \r
\n" ); document.write( "\n" ); document.write( "6x + y = 6
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Algebra.Com's Answer #151048 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
Here's one possible ordered pair: (0,6)\r
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\n" ); document.write( "\n" ); document.write( "6(0)+6=6 ---> 0+6=6 ---> 6=6 ... which is true\r
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\n" ); document.write( "\n" ); document.write( "And another possible ordered pair: (1, 0)\r
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\n" ); document.write( "\n" ); document.write( "6(1)+0=6 ---> 6+0=6 ---> 6=6 ... which is true\r
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\n" ); document.write( "\n" ); document.write( "And another possible ordered pair: (2, -6)\r
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\n" ); document.write( "\n" ); document.write( "6(2)-6=6 ---> 12-6=6 ---> 6=6 ... which is true\r
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\n" ); document.write( "\n" ); document.write( "And another possible ordered pair: (3, -12)\r
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\n" ); document.write( "\n" ); document.write( "6(3)-12=6 ---> 18-12=6 ---> 6=6 ... which is true\r
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\n" ); document.write( "\n" ); document.write( "etc...\r
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\n" ); document.write( "\n" ); document.write( "So this shows us that there are an infinite number of ordered pairs that satisfy this equation. \r
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\n" ); document.write( "\n" ); document.write( "Note: only specific pairs of numbers satisfy the equation. You can't just make up two random numbers and hope that they work.
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