document.write( "Question 27347: Hi
\n" ); document.write( "Triangle ABC has a right angle at A where
\n" ); document.write( "AB=
\n" ); document.write( "[-3]
\n" ); document.write( "[ 3]
\n" ); document.write( "[-2]
\n" ); document.write( "and where CA=
\n" ); document.write( "[-1]
\n" ); document.write( "[ 3]
\n" ); document.write( "[ 6]
\n" ); document.write( "
\n" ); document.write( "{the above vectors should each be in a long square bracket}\r
\n" ); document.write( "\n" ); document.write( "a) Calculate the acute angle at B
\n" ); document.write( "b) Find the length at AB\r
\n" ); document.write( "\n" ); document.write( "I have a total blank on this question. I think the acute angle at B is 45 degrees,as it's a right angle triangle, but I don't know how to prove it using the vector information given. I think i have to find BC but I am stumped on how to do that, let alone find the length of AB.\r
\n" ); document.write( "\n" ); document.write( "Please can you help?\r
\n" ); document.write( "\n" ); document.write( "Thank you
\n" ); document.write( "

Algebra.Com's Answer #15103 by venugopalramana(3286)\"\" \"About 
You can put this solution on YOUR website!
Triangle ABC has a right angle at A where
\n" ); document.write( "AB=....LET US REPRESENT VECTOR AB BY THE SYMBOL {AB}AND MODULUS OF VECTOR AB BY |AB|
\n" ); document.write( "[-3]
\n" ); document.write( "[ 3]
\n" ); document.write( "[-2]...SO {AB}= -3I+3J-2K
\n" ); document.write( "and where CA=
\n" ); document.write( "[-1]
\n" ); document.write( "[ 3]
\n" ); document.write( "[ 6] ...SO {CA}= -1I+3J+6K...HENCE {BC}={AC}-{AB}=-{CA}-{AB}=-(-1I+3J+6K)-
\n" ); document.write( "(-3I+3J-2K}=4I-6J-4K
\n" ); document.write( "{BC}=4I-6J-4K\r
\n" ); document.write( "\n" ); document.write( "{the above vectors should each be in a long square bracket}
\n" ); document.write( "a) Calculate the acute angle at B..
\n" ); document.write( "LET US FIND THIS BY USING
\n" ); document.write( " {AB}.{BC}=|AB|*|BC|COS(B)
\n" ); document.write( "(-3I+3J-2K).(4I-6J-4K)=|-3I+3J-2K|.|4I-6J-4K|COS(B)
\n" ); document.write( "-12-18+8=SQRT(9+9+4)*SQRT(16+36+16)COS(B)
\n" ); document.write( "COS(B)=-22/SQRT(22*68)...THERE IS SOME THING WRONG WITH YOUR NUMBERS ..IF ANGLE B IS ACUTE WE SHOULD GET THIS AS A POSITIVE NUMBER OR LET US TAKE SQRT OF 22*68 AS -38.678.....SO THAT COS(B)=0.5688.... AND ANGLE B =0.9658 RADIANS OR 55.36 DEGREES....
\n" ); document.write( "IF ANGLE A IS RIGHT ANGLE THEN WE SHOULD HAVE
\n" ); document.write( " {CA}.{AB} =0...LET US CHECK..
\n" ); document.write( "(-1I+3J+6K).(-3I+3J-2K)= +3+9-12=0...OK....\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "b) Find the length at AB
\n" ); document.write( "WELL THIS IS |AB|= |-3I+3J-2K|=SQRT(9+9+4)=SQRT(22)=4.69\r
\n" ); document.write( "\n" ); document.write( "I have a total blank on this question. I think the acute angle at B is 45 degrees,as it's a right angle triangle, but I don't know how to prove it using the vector information given. I think i have to find BC but I am stumped on how to do that, let alone find the length of AB.
\n" ); document.write( "Please can you help?
\n" ); document.write( "Thank you
\n" ); document.write( "
\n" ); document.write( "
\n" );