document.write( "Question 200779: 7) The path of a falling object is given by the function where represents the initial velocity in ft/sec and represents the initial height in feet. \r
\n" ); document.write( "\n" ); document.write( "a) If a rock is thrown upward with an initial velocity of 64 feet per second from the top of a 25-foot building, write the height (s) equation using this information.\r
\n" ); document.write( "\n" ); document.write( " Typing hint: Type t-squared as t^2
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\n" ); document.write( "\n" ); document.write( "b) How high is the rock after 1 second?
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\n" ); document.write( "\n" ); document.write( "c) After how many seconds will the graph reach maximum height?
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\n" ); document.write( "\n" ); document.write( "d) What is the maximum height?
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Algebra.Com's Answer #151020 by Alan3354(69443)\"\" \"About 
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a) If a rock is thrown upward with an initial velocity of 64 feet per second from the top of a 25-foot building, write the height (s) equation using this information.
\n" ); document.write( "Typing hint: Type t-squared as t^2
\n" ); document.write( "Answer: h(t) = -16t^2 + 64t + 25 (height above the ground, not the building)
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\n" ); document.write( "b) How high is the rock after 1 second?
\n" ); document.write( "Answer: h(1) = -16 + 64 + 25 = 73 feet
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\n" ); document.write( "c) After how many seconds will the graph reach maximum height?
\n" ); document.write( "Answer: 2
\n" ); document.write( "Show your work here: Solve for h = 25 feet.
\n" ); document.write( "-16t^2 + 64t + 25 = 25
\n" ); document.write( "16t^2 = 64t
\n" ); document.write( "t = 0, t = 4
\n" ); document.write( "The rock is at 25 feet twice, once when launched (t=0) and on its way down (t=4). The time at max height is the center of the 2 times, = 2 seconds.\r
\n" ); document.write( "\n" ); document.write( "d) What is the maximum height?
\n" ); document.write( "Answer: h(2) = -64 + 128 + 25 = 89 feet
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