document.write( "Question 200776: Write an equation of the line that passes through the points (-5,3) and (5,-3). \n" ); document.write( "

Algebra.Com's Answer #151016 by checkley77(12844) $\"\"$ $\"About$

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(-5,3) and (5,-3)
\n" ); document.write( "First we need to find the slope (m) in the line equation Y=mX+b.
\n" ); document.write( "m=(y2-y1)/(x2-x1)
\n" ); document.write( "m=(-3-3)/(5+5)=-6/10 is the slope.
\n" ); document.write( "Now replacing the X+Y terms with one set of X & Y values we solve for the Y intercept (b).
\n" ); document.write( "3=-6/10*-5+b
\n" ); document.write( "3=30/10+b
\n" ); document.write( "b=3-30/10
\n" ); document.write( "b=3-3
\n" ); document.write( "b=0 which is the Y intercept.
\n" ); document.write( "Y=-6x/10 is the line equation which runs through the points (-5,3) & (5,-3).
\n" ); document.write( "Proof:
\n" ); document.write( " $\"+graph%28+300%2C+200%2C+-6%2C+5%2C+-10%2C+10%2C+y+=+-6x%2F10+%29+\"$ (graph 300x200 pixels, x from -6 to 5, y from -10 to 10, y = -6x/10). \r
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