document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=200747>Question 200747</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a cyclist traveled at a rate of 32mph to visit a near by town. The cyclist averaged 10mph on the return trip. If the round trip took 6.3 hours, find the distance to the nearby town.<BR>\n" );
document.write( "D=6.3/(32-10)<BR>\n" );
document.write( "D=.286363\r<BR>\n" );
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document.write( "This is not correct, but I think the opportunity is in the set up.\r<BR>\n" );
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document.write( "Thanks for helping in advance. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #150972 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=150972\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> D=RT<BR>\n" );
document.write( "SEEING AS THE DISTANCES ARE THE SAME WE SET THE TWO DISTANCES EQUAL TO EACH OTHER.<BR>\n" );
document.write( "32X=10(6.3-X)<BR>\n" );
document.write( "32X=63-10X<BR>\n" );
document.write( "32X+10X=63<BR>\n" );
document.write( "42X=63<BR>\n" );
document.write( "X=63/42<BR>\n" );
document.write( "X=1.5 HOURS FOR THE 32 MPH TRIP.<BR>\n" );
document.write( "6.3-1.5=4.8 HOURS FOR THE RETURN TRIP.<BR>\n" );
document.write( "32*1.5=10*4.8<BR>\n" );
document.write( "48=48 MILES IS THE DISTANCE TO THE NEARBY TOWN. </SPAN>\n" );
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