document.write( "Question 192634This question is from textbook
\n" ); document.write( ": How can $54000 be invested, part at 8% annual simple interest and the remainder at 10% annual simple interest, so that the interest earned by the two accounts will be equal \n" ); document.write( "
Algebra.Com's Answer #150957 by Earlsdon(6294)\"\" \"About 
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Let x = the amount invested at 8%, then (54000-x) will be the amount invested at 10%. Convert the percentages to their decimal eqivalents: 8% = 0.08 and 10% = 0.1
\n" ); document.write( "Now you can write the equation:
\n" ); document.write( "0.08x = 0.1($54000-x) Solve this for x.
\n" ); document.write( "0.08x = $5400-0.1x Add 0.1x to both sides of the equation.
\n" ); document.write( "0.18x = $5400 Divide both sides by 0.18
\n" ); document.write( "x = $3000 and $54000-$3000 = $24000
\n" ); document.write( "$3,000 is invested at 8%
\n" ); document.write( "$2,400 is invested at 10%
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