document.write( "Question 200666: Find the vertex and intercepts. f(x)=2x^2+4x-6. please help \n" ); document.write( "
Algebra.Com's Answer #150943 by Alan3354(69443)\"\" \"About 
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Find the vertex and intercepts. f(x)=2x^2+4x-6
\n" ); document.write( "Set equal to zero. The x-intercepts are at f(x) (or y) = 0
\n" ); document.write( "2x^2+4x-6 = 0
\n" ); document.write( "x^2 + 2x - 3 = 0
\n" ); document.write( "(x+3)*(x-1) = 0
\n" ); document.write( "x = -3
\n" ); document.write( "x = 1
\n" ); document.write( "Those are the x-intercepts, or zeroes, of the function.
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\n" ); document.write( "For the y-intercept, let x = 0
\n" ); document.write( "f(0) = -3
\n" ); document.write( "-----------
\n" ); document.write( "The vertex is at x = -b/2a
\n" ); document.write( "x = -2/2 = -1
\n" ); document.write( "f(-1) = -4
\n" ); document.write( "--> the vertex at (-1,-4)
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