document.write( "Question 27145: Find the rightmost digit of 7^(1111). How do i find the remainder when divided by 10 \n" ); document.write( "
Algebra.Com's Answer #15092 by venugopalramana(3286)\"\" \"About 
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WE ARE ONLY INTERESTED IN DIGIT IN UNITS PLACE.SO LET US TRY TO LOOK
\n" ); document.write( "FOR A PATTERN IN THIS.
\n" ); document.write( "POWER......UNITS DIGIT
\n" ); document.write( "7^1=.......................7
\n" ); document.write( "7^2=.......................9
\n" ); document.write( "7^3=.......................3
\n" ); document.write( "7^4-........................1
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\n" ); document.write( "7^5=......................7...SO IT REPEATS NOW..
\n" ); document.write( "HENCE WE HAVE TO FIND 1111 POWER IS UNDER WHICH GROUP..SO DIVIDE IT
\n" ); document.write( "WITH 4 AS THE ABOVE CYCLE REPEATS AFTER FREQUENCY OF 4.IT GIVES US A
\n" ); document.write( "REMAINDER OF 3
\n" ); document.write( "1111=4*277+3....SO IT FALLS UNDER GROUP OF 7^3...SO ITS UNITS DIGIT IS
\n" ); document.write( "3 AS SHOWN ABOVE
\n" ); document.write( "7^1111={7^(4*277)}{7^3)=IT HAS SAME ENDING AS 7^3 WHICH IS 3
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\n" ); document.write( "IF YOU KNOW RESIDUAL CLASSES,CONGRUENCE MODULO,WE CAN USE THAT METHOD
\n" ); document.write( "WE HAVE TO FIND X IN
\n" ); document.write( "7^1111=X(MOD10)
\n" ); document.write( "WE KNOW THAT
\n" ); document.write( "7^2=49=-1(MOD10)
\n" ); document.write( "RAISING TO 555 POWER BOTH SIDES,WE GET,
\n" ); document.write( "(7^2)^555=(-1)^555(MOD10)
\n" ); document.write( "7^1110=-1(MOD10)
\n" ); document.write( "MULTIPLYING WITH 7 NOW WE GET
\n" ); document.write( "7^1111=-7(MOD10)
\n" ); document.write( "7^1111=(10-7)(MOD10)=3(MOD10)
\n" ); document.write( "HENCE 3 IS THE REMAINDER WHEN DIVIDED WITH 10 OR UNITS PLACE HAS 3
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