document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=200636>Question 200636</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A farmer has 240 meters of fencing and wants to enclose a rectangular area of 3200 square meters. What dimensions should he use? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #150892 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=150892\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A farmer has 240 meters of fencing and wants to enclose a rectangular area of 3200 square meters. What dimensions should he use?<BR>\n" );
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document.write( "L*W = 3200<BR>\n" );
document.write( "2L + 2W = 240 --> W = 120-L<BR>\n" );
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document.write( "L*(120-L) = 3200<BR>\n" );
document.write( "120L - L^2 = 3200<BR>\n" );
document.write( "L^2 - 120L + 3200 = 0<BR>\n" );
document.write( "(L-40)*(L-80) = 0<BR>\n" );
document.write( "L = 40, W = 80<BR>\n" );
document.write( "L = 80, W = 40 </SPAN>\n" );
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