document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=200588>Question 200588</A>: <I><SPAN STYLE=\"word-break: break-all;\"> somebody said the solution for:squareroot of negative w, then subracting 6=w is negative 4 and negative 9.Then he said we take negative 9 because the squareroot of 9 (after substituding w with -9) is -3.I am confussed.please explain this to me.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #150889 by </B><A HREF=/tutors/aboutme.mpl?userid=RAY100><B>RAY100(1637)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=RAY100><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=150889\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> sqrt(-w)  -6 =w<BR>\n" );
document.write( "sqrt(-w) = w+6<BR>\n" );
document.write( "SQUARE  BOTH  SIDES<BR>\n" );
document.write( "(-w) = (w+6)^2 = w^2 +12w +36<BR>\n" );
document.write( "0 = w^2 +13w +36<BR>\n" );
document.write( "FACTOR<BR>\n" );
document.write( "0 = ( w+9)(w+4)<BR>\n" );
document.write( "(w+9) =0,,,w=(-9),,,,,,,(w+4)=0,,,,,w=(-4),,,,so  far  ok  to  advise  <BR>\n" );
document.write( ".<BR>\n" );
document.write( "Checking<BR>\n" );
document.write( "w=-4,,,,,sqrt -(-4)  -6 = (-4)<BR>\n" );
document.write( "sqrt(+4) -6 = -4<BR>\n" );
document.write( "+2 -6 = -4,,,,,,ok,,,,,,,,,,,,,,,,,,pls  note,,,,,,opposite  advise<BR>\n" );
document.write( ".<BR>\n" );
document.write( "w=(-9),,,,,,sqrt -(-9) -6 = (-9)<BR>\n" );
document.write( "sqrt (+9) -6 = (-9)<BR>\n" );
document.write( "3 - 6 = -9<BR>\n" );
document.write( "-3 = -9,,,,,NO,,,,,,therefore  not  answer,,,,,note,,,opposite  advise </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );