document.write( "Question 200548: There are 15 blue jays and 14 orioles perched in 3 trees . each tree has at least 4 blue jays, and 2 orioles, if no tree has more orioles than blue jays, then the largest number of birds that can be in one tree is\r
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document.write( "a)11 b) 12 c) 13 d) 14 e) 15 \n" );
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Algebra.Com's Answer #150836 by Edwin McCravy(20056)![]() ![]() You can put this solution on YOUR website! There are 15 blue jays and 14 orioles perched in 3 trees . each tree has at least 4 blue jays, and 2 orioles, if no tree has more orioles than blue jays, then the largest number of birds that can be in one tree is \n" ); document.write( "a)11 b) 12 c) 13 d) 14 e) 15 \n" ); document.write( " \r\n" ); document.write( "\r\n" ); document.write( "Pretend we have three trees, TREES 1, 2, and 3 and \r\n" ); document.write( "we are going to place the birds in the trees so that \r\n" ); document.write( "TREE 1 will have as many birds as possible, under the \r\n" ); document.write( "given conditions.\r\n" ); document.write( "\r\n" ); document.write( "Make this chart\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( " TREE 1 TREE 2 TREE 3 \r\n" ); document.write( "No. of Blue Jays\r\n" ); document.write( "No. of Orioles\r\n" ); document.write( "\r\n" ); document.write( "We start by placing 4 bluejays and 2 orioles in each tree,\r\n" ); document.write( "since each tree must have that:\r\n" ); document.write( "\r\n" ); document.write( " TREE 1 TREE 2 TREE 3 \r\n" ); document.write( "No. of Blue Jays 4 4 4 \r\n" ); document.write( "No. of Orioles 2 2 2\r\n" ); document.write( "\r\n" ); document.write( "So \r\n" ); document.write( "\r\n" ); document.write( "1. Now we have accounted for 12 of the 15 blue jays, leaving \r\n" ); document.write( "3 more blue jays to place.\r\n" ); document.write( "\r\n" ); document.write( "and\r\n" ); document.write( "\r\n" ); document.write( "2. We have accounted for 6 of the 14 orioles, leaving 8 more orioles\r\n" ); document.write( "to place. \r\n" ); document.write( " \r\n" ); document.write( "Now since we're letting Tree 1 have the most birds, let's put all \r\n" ); document.write( "three of the remaining blue jays in TREE 1, making there be 7 Blue \r\n" ); document.write( "Jays there.\r\n" ); document.write( "\r\n" ); document.write( " TREE 1 TREE 2 TREE 3 \r\n" ); document.write( "No. of Blue Jays 7 4 4 \r\n" ); document.write( "No. of Orioles 2 2 2\r\n" ); document.write( "\r\n" ); document.write( "Now we have placed all the Blue Jays. We still have 8 more orioles\r\n" ); document.write( "to place. We can only put 5 more orioles in TREE 1, because TREE 1\r\n" ); document.write( "can't have more orioles than blue jays. So we have\r\n" ); document.write( "\r\n" ); document.write( " TREE 1 TREE 2 TREE 3 \r\n" ); document.write( "No. of Blue Jays 7 4 4 \r\n" ); document.write( "No. of Orioles 7 2 2\r\n" ); document.write( "\r\n" ); document.write( "That leaves 3 more orioles and so we can put two of them in in TREE 2 \r\n" ); document.write( "and 1 in TREE 2, or vice-versa. So we either end up with THIS:\r\n" ); document.write( "\r\n" ); document.write( " TREE 1 TREE 2 TREE 3 \r\n" ); document.write( "No. of Blue Jays 7 4 4 \r\n" ); document.write( "No. of Orioles 7 4 3 \r\n" ); document.write( "\r\n" ); document.write( "OR with THIS:\r\n" ); document.write( "\r\n" ); document.write( " TREE 1 TREE 2 TREE 3 \r\n" ); document.write( "No. of Blue Jays 7 4 4 \r\n" ); document.write( "No. of Orioles 7 3 4 \r\n" ); document.write( "\r\n" ); document.write( "Either way TREE 1 has 14 birds. So that's the answer d).\r\n" ); document.write( "\r\n" ); document.write( "Edwin\n" ); document.write( " |