document.write( "Question 27689: A jetliner flying with the wind traveled 3600 km in 6 hours. The return trip, against the wind, took 8 hours. Find the rate at which the jet flew in still air.
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Algebra.Com's Answer #15083 by Paul(988) ![]() You can put this solution on YOUR website! Let the speed of the plane be x \n" ); document.write( "Let the speed of the wind be y\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "6(x+y)=3600 (solve for y) \n" ); document.write( "6x+6y=3600 \n" ); document.write( "6y=3600-6x \n" ); document.write( "y=600-x (subsitution)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "8(x-y)=3600 \n" ); document.write( "8x-8y=3600 (apply subsitution) \n" ); document.write( "8x-8(600-x)=3600 \n" ); document.write( "8x+8x-4800=3600 \n" ); document.write( "16x=8400 \n" ); document.write( "x=525\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "y=600-525 \n" ); document.write( "y=75\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Hence, the speed of the plane in still air is 525mph and the speed of the wind is 75mph. \n" ); document.write( "PAUL. \n" ); document.write( " |