document.write( "Question 200550This question is from textbook Beginning Algebra
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document.write( ": Hello,
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document.write( "I really need help with the following word problem: The engineering club ran a coffee and donut sale to raise money for the club's activities. The first week, they made a profit of $200. The second week, they sold 3 times as many donuts, but 1/2 the number of coffees, and made a profit of $225. If the profit for each donut was $.50 and the profit for each coffee was $.75, how many donuts and coffees did they sell the first week?\r
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document.write( "I would greatly appreciate any help. \n" );
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Algebra.Com's Answer #150815 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! The first week, they made a profit of $200. The second week, they sold 3 times \n" ); document.write( " as many donuts, but 1/2 the number of coffees, and made a profit of $225. \n" ); document.write( " If the profit for each donut was $.50 and the profit for each coffee was $.75, \n" ); document.write( " how many donuts and coffees did they sell the first week? \n" ); document.write( ": \n" ); document.write( "let d = no. of donuts sold the 1st week \n" ); document.write( "let c = no. of coffees sold the 1st week \n" ); document.write( ": \n" ); document.write( "First week equation: \n" ); document.write( ".50d + .75c = 200 \n" ); document.write( ": \n" ); document.write( "2nd week equation: \n" ); document.write( ".50(3d) + .75(.5c) = 225 \n" ); document.write( "1.50d + .375c = 225 \n" ); document.write( ": \n" ); document.write( "Multiply the above equation by 2, subtract the first equation \n" ); document.write( "3d + .75c = 450 \n" ); document.write( ".5d +.75c = 200 \n" ); document.write( "-----------------Subtraction eliminate c, find d \n" ); document.write( "2.5d = 250 \n" ); document.write( "d = \n" ); document.write( "d = 100 donuts, the 1st week \n" ); document.write( ": \n" ); document.write( "Find c using the 1st equation \n" ); document.write( ".50(100) + .75c = 200 \n" ); document.write( "50 + .75c = 200 \n" ); document.write( ".75c = 200 - 50 \n" ); document.write( ".75c = 150 \n" ); document.write( "c = \n" ); document.write( "c = 200 coffees the 1st week \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Check solutions in the 2nd week equation \n" ); document.write( "1.50d + .375c = 225 \n" ); document.write( "1.50(100) + .375(200) = \n" ); document.write( "150 + 75 = 225 \n" ); document.write( " |