document.write( "Question 200417This question is from textbook
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document.write( ": in canada, medicine and cranbrook are 300Km apart. Harry rides 20 Km per hr faster than yoshi rides his yamaha. find harry's average speed if he travels from cranbrook to medicine hat in 1.1/4 less time than yoshi. \n" );
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Algebra.Com's Answer #150814 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! In Canada, Medicine Hat and Cranbrook are 300Km apart. Harry rides 20 Km per \n" ); document.write( " hr faster than Yoshi rides his Yamaha. Find Harry's average speed if he \n" ); document.write( " travels from Cranbrook to Medicine hat in 1.1/4 less time than Yoshi. \n" ); document.write( ": \n" ); document.write( "Let s = H's speed \n" ); document.write( "then \n" ); document.write( "(s-20) = Y's speed \n" ); document.write( ": \n" ); document.write( "Write a time equation; Time = \n" ); document.write( "H's time + 1.25 hrs = Y's time \n" ); document.write( " \n" ); document.write( "Multiply equation by s(s-20), results: \n" ); document.write( "300(s-20) + 1.25s(s-20) = 300s \n" ); document.write( ": \n" ); document.write( "300s - 6000 + 1.25s^2 - 25s = 300s \n" ); document.write( "Arrange as a quadratic equation \n" ); document.write( "1.25s^2 + 300s - 300s - 25s - 6000 = 0 \n" ); document.write( ": \n" ); document.write( "1.25s^2 - 25s - 6000 = 0 \n" ); document.write( "Divide equation by 1.25 to simplify: \n" ); document.write( "s^2 - 20s - 4800 = 0 \n" ); document.write( "Factor \n" ); document.write( "(s - 80)(s + 60) = 0 \n" ); document.write( "The positive solution \n" ); document.write( "s = 80 km/hr is H's average speed \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Check solution by finding the times; (60 km/hr is Y's speed) \n" ); document.write( "300/60 = 5 hrs \n" ); document.write( "300/80 = 3.75 hrs \n" ); document.write( "--------------- \n" ); document.write( "differ = 1.25 hr\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |