document.write( "Question 200513: the altitude 'h' of a cone varies directly as its volume and inversely as the square of the radius of its base. if a cone with an altitude of 32 centimeters and a radius of the base is 4 centimeters and has a volume of $\"512pi%2F3\"$ cubic centimeters, find the altitude of a cone with a volume of 6pi cubic centimeters and the radius of the base is 3 centimeters \n" ); document.write( "

Algebra.Com's Answer #150810 by ankor@dixie-net.com(22740) $\"\"$ $\"About$

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The altitude 'h' of a cone varies directly as its volume and inversely as the
\n" ); document.write( " square of the radius of its base. If a cone with an altitude of 32 centimeters
\n" ); document.write( " and a radius of the base is 4 centimeters and has a volume of 512pi/3 cubic
\n" ); document.write( " centimeters, find the altitude of a cone with a volume of 6pi cubic centimeters
\n" ); document.write( " and the radius of the base is 3 centimeters
\n" ); document.write( ":
\n" ); document.write( "\"the altitude 'h' of a cone varies directly as its volume and inversely as the square of the radius of its base.\" We can write this as:
\n" ); document.write( "h = $\"v%2Fr%5E2\"$
\n" ); document.write( ":
\n" ); document.write( "\"find the altitude of a cone with a volume of 6pi cubic centimeters and the
\n" ); document.write( " radius of the base is 3 centimeters\"
\n" ); document.write( "h = $\"%286pi%29%2F3%5E2\"$
\n" ); document.write( "h = $\"%2818.85%29%2F9\"$
\n" ); document.write( "h = 2.09 cm is the height \n" ); document.write( "

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