document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=200511>Question 200511</A>: <I><SPAN STYLE=\"word-break: break-all;\"> log 5 10 = log 5 30 =\r<BR>\n" );
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document.write( "ln20 - ln5 =\r<BR>\n" );
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document.write( "2 log 3 = log 5 - log 15 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #150802 by </B><A HREF=/tutors/aboutme.mpl?userid=solver91311><B>solver91311(24713)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=solver91311><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=solver91311><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=150802\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <font face=\"Garamond\" size=\"+2\">\r<BR>\n" );
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document.write( "Your first problem makes no sense.  <IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\Large \log_5(10) \neq \log_5(30)\">.  So the only answer possible is:\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\Large \log_5(10) = \log_5(30) =\"> False, meaning the statement \"the base 5 log of 10 is equal to the base 5 log of 30\" is a false statement.\r<BR>\n" );
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document.write( "The difference of the logs is the log of the quotient, so:\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\LARGE \ \ \ \ \ \ \ \ \ \ \ln(20) - \ln(5) = \ln\left(\frac{20}{5}\right) = \ln(4)\">\r<BR>\n" );
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document.write( "Your third problem makes no sense either.  How can <IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\Large 2\log(3) = \log(3^2) =\log(9)\"> be equal to <IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\Large \log\left(\frac{1}{3}\)\">?\r<BR>\n" );
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document.write( "John<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\LARGE e^{i\pi} + 1 = 0\"><BR>\n" );
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