document.write( "Question 200406: A boat took 5 hours to travel 60 kilometers up a river against a current. The return trip took 3 hours .Find the speed of the boat in still water and the speed of the current.\r
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document.write( "Solve the linear system\r
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document.write( "x-2/3 + y+1/5 = 2\r
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document.write( "x+2/7 - y+5/3 = -2\r
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Algebra.Com's Answer #150793 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! A boat took 5 hours to travel 60 kilometers up a river against a current. \n" ); document.write( " The return trip took 3 hours \n" ); document.write( " .Find the speed of the boat in still water and the speed of the current. \n" ); document.write( ": \n" ); document.write( "Let x = speed of the boat in still water \n" ); document.write( "Let y = speed of the current \n" ); document.write( "then \n" ); document.write( "(x+y) = speed downstream \n" ); document.write( "(x-y) = speed upstream \n" ); document.write( ": \n" ); document.write( "Write a dist equation for each trip: Dist = time * speed \n" ); document.write( ": \n" ); document.write( "5(x - y) = 60 \n" ); document.write( "3(x + y) = 60 \n" ); document.write( ": \n" ); document.write( "Simplify, divide the 1st equation by 5, and the 2nd equation by 3, results: \n" ); document.write( "x - y = 12 \n" ); document.write( "x + y = 20 \n" ); document.write( "--------------addition eliminates y, find x \n" ); document.write( "2x = 32 \n" ); document.write( "x = 16 km/hr boat speed in still water \n" ); document.write( "and \n" ); document.write( "16 + y = 20 \n" ); document.write( "y = 20 - 16 \n" ); document.write( "y = 4 km/hr current speed \n" ); document.write( ": \n" ); document.write( "Check solution in original 1st equation \n" ); document.write( "5(16 - 4) = 60 \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Solve the linear system \n" ); document.write( "Assume it's \n" ); document.write( " \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( "Get rid of the denominators, \n" ); document.write( " multiply the 1st eq by 15, results: \n" ); document.write( "5(x-2) + 3(y+1) = 15(2) \n" ); document.write( "5x - 10 + 3y + 3 = 30 \n" ); document.write( "5x + 3y - 7 = 30 \n" ); document.write( "5x + 3y = 30 + 7 \n" ); document.write( "5x + 3y = 37 \n" ); document.write( ": \n" ); document.write( "Multiply the 2nd equation by 21, results: \n" ); document.write( "3(x+2) - 7(y+5) = 21(-2) \n" ); document.write( "3x + 6 - 7y - 35 = -42 \n" ); document.write( "3x - 7y - 29 = - 42 \n" ); document.write( "3x - 7y = -42 + 29 \n" ); document.write( "3x - 7y = -13 \n" ); document.write( ": \n" ); document.write( "Multiply the 1st equation by 3: \n" ); document.write( "15x + 9y = 3(37) \n" ); document.write( "15x + 9y = 111 \n" ); document.write( ": \n" ); document.write( "Multiply the 2nd equation by 5 \n" ); document.write( "15x - 35y = 5(-13) \n" ); document.write( "15x - 35y = -65 \n" ); document.write( ": \n" ); document.write( "Use elimination \n" ); document.write( "15x + 9y = 111 \n" ); document.write( "15x - 35y = -65 \n" ); document.write( "------------------subtraction eliminate x \n" ); document.write( "+44y = 176 \n" ); document.write( "y = \n" ); document.write( "y = 4 \n" ); document.write( ": \n" ); document.write( "Use the equation: 5x + 3y = 37 to find x \n" ); document.write( "5x + 3(4) = 37 \n" ); document.write( "5x + 12 = 37 \n" ); document.write( "5x = 37 - 12 \n" ); document.write( "5x = 25 \n" ); document.write( "x = \n" ); document.write( "x = 5 \n" ); document.write( ": \n" ); document.write( "x = 5, y = 4 is the solution \n" ); document.write( "; \n" ); document.write( ": \n" ); document.write( "Check solution in the 1st original equation \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |