document.write( "Question 200406: A boat took 5 hours to travel 60 kilometers up a river against a current. The return trip took 3 hours .Find the speed of the boat in still water and the speed of the current.\r
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\n" ); document.write( "\n" ); document.write( "Solve the linear system\r
\n" ); document.write( "\n" ); document.write( "x-2/3 + y+1/5 = 2\r
\n" ); document.write( "\n" ); document.write( "x+2/7 - y+5/3 = -2\r
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Algebra.Com's Answer #150793 by ankor@dixie-net.com(22740)\"\" \"About 
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A boat took 5 hours to travel 60 kilometers up a river against a current.
\n" ); document.write( " The return trip took 3 hours
\n" ); document.write( " .Find the speed of the boat in still water and the speed of the current.
\n" ); document.write( ":
\n" ); document.write( "Let x = speed of the boat in still water
\n" ); document.write( "Let y = speed of the current
\n" ); document.write( "then
\n" ); document.write( "(x+y) = speed downstream
\n" ); document.write( "(x-y) = speed upstream
\n" ); document.write( ":
\n" ); document.write( "Write a dist equation for each trip: Dist = time * speed
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\n" ); document.write( "5(x - y) = 60
\n" ); document.write( "3(x + y) = 60
\n" ); document.write( ":
\n" ); document.write( "Simplify, divide the 1st equation by 5, and the 2nd equation by 3, results:
\n" ); document.write( "x - y = 12
\n" ); document.write( "x + y = 20
\n" ); document.write( "--------------addition eliminates y, find x
\n" ); document.write( "2x = 32
\n" ); document.write( "x = 16 km/hr boat speed in still water
\n" ); document.write( "and
\n" ); document.write( "16 + y = 20
\n" ); document.write( "y = 20 - 16
\n" ); document.write( "y = 4 km/hr current speed
\n" ); document.write( ":
\n" ); document.write( "Check solution in original 1st equation
\n" ); document.write( "5(16 - 4) = 60
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\n" ); document.write( ":
\n" ); document.write( "Solve the linear system
\n" ); document.write( "Assume it's
\n" ); document.write( "\"%28%28x-2%29%29%2F3\" + \"%28%28y%2B1%29%29%2F5\" = 2
\n" ); document.write( "\"%28%28x%2B2%29%29%2F7\" - \"%28%28y%2B5%29%29%2F3\" = -2
\n" ); document.write( ":
\n" ); document.write( "Get rid of the denominators,
\n" ); document.write( " multiply the 1st eq by 15, results:
\n" ); document.write( "5(x-2) + 3(y+1) = 15(2)
\n" ); document.write( "5x - 10 + 3y + 3 = 30
\n" ); document.write( "5x + 3y - 7 = 30
\n" ); document.write( "5x + 3y = 30 + 7
\n" ); document.write( "5x + 3y = 37
\n" ); document.write( ":
\n" ); document.write( "Multiply the 2nd equation by 21, results:
\n" ); document.write( "3(x+2) - 7(y+5) = 21(-2)
\n" ); document.write( "3x + 6 - 7y - 35 = -42
\n" ); document.write( "3x - 7y - 29 = - 42
\n" ); document.write( "3x - 7y = -42 + 29
\n" ); document.write( "3x - 7y = -13
\n" ); document.write( ":
\n" ); document.write( "Multiply the 1st equation by 3:
\n" ); document.write( "15x + 9y = 3(37)
\n" ); document.write( "15x + 9y = 111
\n" ); document.write( ":
\n" ); document.write( "Multiply the 2nd equation by 5
\n" ); document.write( "15x - 35y = 5(-13)
\n" ); document.write( "15x - 35y = -65
\n" ); document.write( ":
\n" ); document.write( "Use elimination
\n" ); document.write( "15x + 9y = 111
\n" ); document.write( "15x - 35y = -65
\n" ); document.write( "------------------subtraction eliminate x
\n" ); document.write( "+44y = 176
\n" ); document.write( "y = \"176%2F44\"
\n" ); document.write( "y = 4
\n" ); document.write( ":
\n" ); document.write( "Use the equation: 5x + 3y = 37 to find x
\n" ); document.write( "5x + 3(4) = 37
\n" ); document.write( "5x + 12 = 37
\n" ); document.write( "5x = 37 - 12
\n" ); document.write( "5x = 25
\n" ); document.write( "x = \"25%2F5\"
\n" ); document.write( "x = 5
\n" ); document.write( ":
\n" ); document.write( "x = 5, y = 4 is the solution
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\n" ); document.write( ":
\n" ); document.write( "Check solution in the 1st original equation
\n" ); document.write( "\"%28%28x-2%29%29%2F3\" + \"%28%28y%2B1%29%29%2F5\" = 2
\n" ); document.write( "\"%28%285-2%29%29%2F3\" + \"%28%284%2B1%29%29%2F5\" = 2
\n" ); document.write( "\"3%2F3\" + \"5%2F5\" = 2
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