document.write( "Question 200538: please help me solve this equation
\n" ); document.write( "$1000 is invested at 4% for 3 years. How much will the account be worth if the interest is compounded monthly?
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Algebra.Com's Answer #150785 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "\n" ); document.write( "\"A=p%281%2Br%2Fn%29%5E%28n%2At%29\" Start with the compound interest formula\r
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\n" ); document.write( "\n" ); document.write( "\"A=1000%281%2B0.04%2F12%29%5E%2812%2A3%29\" Plug in p=1000 (the amount invested), r=0.04 (this is the decimal form of 4% interest), n=12 (compounded monthly), and t=3 (3 years)\r
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\n" ); document.write( "\n" ); document.write( "\"A=1000%281%2B0.00333333%29%5E%2812%2A3%29\" Divide 0.04 by 12 to get 0.00333333 (this value is approximate)\r
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\n" ); document.write( "\n" ); document.write( "\"A=1000%281%2B0.00333333%29%5E%2836%29\" Multiply the exponents 12 and 3 to get 36\r
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\n" ); document.write( "\n" ); document.write( "\"A=1000%281.00333333%29%5E%2836%29\" Add 1 and 0.00333333 to get 1.00333333\r
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\n" ); document.write( "\n" ); document.write( "\"A=1000%281.1272717%29\" Raise 1.00333333 to the 36th power to get 1.1272717\r
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\n" ); document.write( "\n" ); document.write( "\"A=1127.2717\" Multiply 1000 and 1.127137 to get 1,127.2717\r
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\n" ); document.write( "\n" ); document.write( "So if you invest $1,000 at an interest rate of 4%, which is compounded 12 times a year for 3 years, the return is about $1,127.27 (which is rounded to the nearest cent)
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