document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=200529>Question 200529</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The brackets may have confused in the previous version of the question I submitted. \r<BR>\n" );
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document.write( "This a question for solving electrical resistance in a parallel circuit. The formula is 1/Rt = 1/R1 + 1/R2 +1/R3 + 1/Rn.\r<BR>\n" );
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document.write( "Rt represents total resistance the other fractions are separate branch resistances.\r<BR>\n" );
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document.write( "1/Rt= 1/12 + 1/15 + 1/5<BR>\n" );
document.write( "Rt=?\r<BR>\n" );
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document.write( "Thank you  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #150766 by </B><A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><B>jim_thompson5910(35256)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=150766\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=1%2F%28R%5Bt%5D%29=1%2F12%2B1%2F15%2B1%2F5 ALIGN=MIDDLE  ALT=\"1%2F%28R%5Bt%5D%29=1%2F12%2B1%2F15%2B1%2F5\"   DISABLED_style= \"max-width:90%; height:auto;\" > Start with the given equation.\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=60%2Across%28R%5Bt%5D%29%281%2Fcross%28R%5Bt%5D%29%29=cross%2860%29%5E5%2AR%5Bt%5D%281%2Fcross%2812%29%29%2Bcross%2860%29%5E4%2AR%5Bt%5D%281%2Fcross%2815%29%29%2Bcross%2860%29%5E12%2AR%5Bt%5D%281%2Fcross%285%29%29 ALIGN=MIDDLE   DISABLED_style= \"max-width:90%; height:auto;\" > Multiply EVERY term by the LCD <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=60R%5Bt%5D ALIGN=MIDDLE  ALT=\"60R%5Bt%5D\"   DISABLED_style= \"max-width:90%; height:auto;\" > to clear out the fractions.\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=60=5R%5Bt%5D%2B4R%5Bt%5D%2B12R%5Bt%5D ALIGN=MIDDLE  ALT=\"60=5R%5Bt%5D%2B4R%5Bt%5D%2B12R%5Bt%5D\"   DISABLED_style= \"max-width:90%; height:auto;\" > Multiply and simplify\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=60=21R%5Bt%5D ALIGN=MIDDLE  ALT=\"60=21R%5Bt%5D\"   DISABLED_style= \"max-width:90%; height:auto;\" > Combine like terms.\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=60%2F21=R%5Bt%5D ALIGN=MIDDLE  ALT=\"60%2F21=R%5Bt%5D\"   DISABLED_style= \"max-width:90%; height:auto;\" > Divide both sides by 21 to isolate <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=R%5Bt%5D ALIGN=MIDDLE  ALT=\"R%5Bt%5D\"   DISABLED_style= \"max-width:90%; height:auto;\" >.\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=R%5Bt%5D=60%2F21 ALIGN=MIDDLE  ALT=\"R%5Bt%5D=60%2F21\"   DISABLED_style= \"max-width:90%; height:auto;\" > Rearrange the equation.\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=R%5Bt%5D=20%2F7 ALIGN=MIDDLE  ALT=\"R%5Bt%5D=20%2F7\"   DISABLED_style= \"max-width:90%; height:auto;\" > Reduce\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=R%5Bt%5D=2.8571 ALIGN=MIDDLE  ALT=\"R%5Bt%5D=2.8571\"   DISABLED_style= \"max-width:90%; height:auto;\" > Approximate the right side\r<BR>\n" );
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document.write( "So the total resistance is approximately 2.8571 ohms (assuming that's the unit you're working with). </SPAN>\n" );
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