document.write( "Question 200501: Steve traveled 600 miles at a certain speed. Had he gone 20mph faster, the trip would have taken 1 hour less. Find the speed of his vehicle. \r
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Algebra.Com's Answer #150756 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!

\n" ); document.write( "Remember, the distance-rate-time formula is \r
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\n" ); document.write( "\n" ); document.write( "\"d=rt\"\r
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\n" ); document.write( "\n" ); document.write( "Since he \"traveled 600 miles at a certain speed\", this means that the first equation is \"600=rt\"\r
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\n" ); document.write( "\n" ); document.write( "The statemtent \"Had gone 20mph faster, the trip would have taken 1 hour less\", tells us that the next equation is \"600=%28r%2B20%29%28t-1%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"600=rt\" Start with the first equation.\r
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\n" ); document.write( "\n" ); document.write( "\"600%2Fr=t\" Divide both sides by r.\r
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\n" ); document.write( "\n" ); document.write( "\"t=600%2Fr\" Rearrange the equation\r
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\n" ); document.write( "\n" ); document.write( "\"600=%28r%2B20%29%28t-1%29\" Move onto the second equation.\r
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\n" ); document.write( "\n" ); document.write( "\"600=%28r%2B20%29%28600%2Fr-1%29\" Plug in \"t=600%2Fr\" \r
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\n" ); document.write( "\n" ); document.write( "\"600=600-r%2B12000%2Fr-20\" FOIL\r
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\n" ); document.write( "\n" ); document.write( "\"600r=600r-r%5E2%2B12000-20r\" Multiply every term by the LCD \"r\" to clear the fractions.\r
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\n" ); document.write( "\n" ); document.write( "\"0=600r-r%5E2%2B12000-20r-600r\" Subtract \"600r\" from both sides.\r
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\n" ); document.write( "\n" ); document.write( "\"0=-r%5E2-20r%2B12000\" Combine and rearrange the terms.\r
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\n" ); document.write( "\n" ); document.write( "Let's use the quadratic formula to solve for r\r
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\n" ); document.write( "\n" ); document.write( "\"r+=+%28-b+%2B-+sqrt%28+b%5E2-4ac+%29%29%2F%282a%29\" Start with the quadratic formula\r
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\n" ); document.write( "\n" ); document.write( "\"r+=+%28-%28-20%29+%2B-+sqrt%28+%28-20%29%5E2-4%28-1%29%2812000%29+%29%29%2F%282%28-1%29%29\" Plug in \"a=-1\", \"b=-20\", and \"c=12000\"\r
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\n" ); document.write( "\n" ); document.write( "\"r+=+%2820+%2B-+sqrt%28+%28-20%29%5E2-4%28-1%29%2812000%29+%29%29%2F%282%28-1%29%29\" Negate \"-20\" to get \"20\". \r
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\n" ); document.write( "\n" ); document.write( "\"r+=+%2820+%2B-+sqrt%28+400-4%28-1%29%2812000%29+%29%29%2F%282%28-1%29%29\" Square \"-20\" to get \"400\". \r
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\n" ); document.write( "\n" ); document.write( "\"r+=+%2820+%2B-+sqrt%28+400--48000+%29%29%2F%282%28-1%29%29\" Multiply \"4%28-1%29%2812000%29\" to get \"-48000\"\r
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\n" ); document.write( "\n" ); document.write( "\"r+=+%2820+%2B-+sqrt%28+400%2B48000+%29%29%2F%282%28-1%29%29\" Rewrite \"sqrt%28400--48000%29\" as \"sqrt%28400%2B48000%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"r+=+%2820+%2B-+sqrt%28+48400+%29%29%2F%282%28-1%29%29\" Add \"400\" to \"48000\" to get \"48400\"\r
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\n" ); document.write( "\n" ); document.write( "\"r+=+%2820+%2B-+sqrt%28+48400+%29%29%2F%28-2%29\" Multiply \"2\" and \"-1\" to get \"-2\". \r
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\n" ); document.write( "\n" ); document.write( "\"r+=+%2820+%2B-+220%29%2F%28-2%29\" Take the square root of \"48400\" to get \"220\". \r
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\n" ); document.write( "\n" ); document.write( "\"r+=+%2820+%2B+220%29%2F%28-2%29\" or \"r+=+%2820+-+220%29%2F%28-2%29\" Break up the expression. \r
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\n" ); document.write( "\n" ); document.write( "\"r+=+%28240%29%2F%28-2%29\" or \"r+=++%28-200%29%2F%28-2%29\" Combine like terms. \r
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\n" ); document.write( "\n" ); document.write( "\"r+=+-120\" or \"r+=+100\" Simplify.\r
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\n" ); document.write( "\n" ); document.write( "Since a negative speed doesn't make any sense, this means that the only solution is \"r+=+100\"\r
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\n" ); document.write( "\n" ); document.write( "Answer:\r
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\n" ); document.write( "\n" ); document.write( "So the speed of his vehicle is 100 mph\r
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\n" ); document.write( "\n" ); document.write( "If you have any questions, email me at jim_thompson5910@hotmail.com.
\n" ); document.write( "Check out my website if you are interested in tutoring.
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