document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=200519>Question 200519</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the equation of the circle which has a diameter whose endpoints are (-6,3) and (2,5) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #150755 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=150755\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> the center of the circle is the midpoint of the diameter\r<BR>\n" );
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document.write( "(-6+2)/2 = -2\r<BR>\n" );
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document.write( "(3+5)/2 = 4  ___  so the center is (-2,4)\r<BR>\n" );
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document.write( "the radius is half the length of the diameter\r<BR>\n" );
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document.write( "sqrt[(2+6)^2 + (5-3)^2] = sqrt(68) = 2 sqrt(17)<BR>\n" );
document.write( "so radius is sqrt(17)\r<BR>\n" );
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document.write( "using the general equation for a circle ___ (x+2)^2 + (y-4)^2 = 17 </SPAN>\n" );
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