document.write( "Question 200523: David and Carl go mounting climbing. David starts 30 minutes before Carl and climbs at 18 ft/min. Carl climbs at 20 ft/min. How far up the mountain will they meet.\r
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document.write( "20t = 18(t +30)
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document.write( "20t = 18t + 540
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document.write( "2t = 540
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document.write( "t = 270\r
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document.write( "This can't be the correct answer because David has already climbed 540 feet even before Carl starts climbing. Therefore meeting at 270 ft. is the wrong answer. What is the answer and what am I doing wrong? \n" );
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Algebra.Com's Answer #150747 by rfer(16322)![]() ![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "the difference in speed 20-18=2 \n" ); document.write( "so he will gain 2 ft/min \n" ); document.write( "or 270 min to meet \n" ); document.write( "you just need to go a little further \n" ); document.write( "270 min * 20 ft/min=5400 ft up the mountain \n" ); document.write( "270 min * 18 ft/min=4860 ft + 540 ft ahead=5400 ft up mountain \n" ); document.write( " |