document.write( "Question 200475: $\"+log+%28x%29+%2B+log+%28+x+%2B+3+%29+=+1+\"$ \n" ); document.write( "

Algebra.Com's Answer #150725 by nerdybill(7384) $\"\"$ $\"About$

You can put this solution on YOUR website!
Apply log rules:
\n" ); document.write( "log (x) + log ( x + 3 ) = 1
\n" ); document.write( "log [(x)(x+3)] = 1
\n" ); document.write( "(x)(x+3) = 10^1
\n" ); document.write( "x^2 + 3x = 10
\n" ); document.write( "x^2 + 3x - 10 = 0
\n" ); document.write( "(x+5)(x-2) = 0
\n" ); document.write( "x = {-5, 2}
\n" ); document.write( "Throwing out the negative solution we are left with:
\n" ); document.write( "x = 2
\n" ); document.write( " \n" ); document.write( "

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