document.write( "Question 27694: I have to put this equation y=x^2-2x-15 into this form y=a(x-h)^2+k. I have to find the line of symmetry. (h,k)=vertex I think you use complete the square technique. Please help. thanks \n" ); document.write( "
Algebra.Com's Answer #15071 by venugopalramana(3286)![]() ![]() You can put this solution on YOUR website! I have to put this equation y=x^2-2x-15 into this form y=a(x-h)^2+k. \n" ); document.write( "MAKE A PERFECT SQUARE USING X^2 AND X TERMS.ADD AND SUBTRACT THE REQUIRED CONSTANT FOR THE PURPOSE. \n" ); document.write( "Y=(X-1)^2-1-15=(X-1)^2-16...COMPARING WITH THE ABOVE \n" ); document.write( "y=a(x-h)^2+k. \n" ); document.write( "WE GET A=1 AND K=-16 \n" ); document.write( " I have to find the line of symmetry. \n" ); document.write( "X-1=0 IS THE LINE OF SYMMETRY SINCE ON EITHER SIDE OF X=1,WE GET SYMMETRIC/SAME VALUES FOR Y..AT X=1+2=3..Y IS -12 AND AT X=1-2=-1 ALSO WE GET Y=-12 \n" ); document.write( " (h,k)=vertex I think you use complete the square technique. \n" ); document.write( "YA ..THE VERTEX AS YOU SHOULD KNOW NOW IS AT X=1 AND AT X=1 ,Y=-16 .SO (1,-16) IS THE VERTEX \n" ); document.write( "THE VCGRAPH WILL LOOK LIKE THIS \n" ); document.write( " \n" ); document.write( " Please help. thanks \n" ); document.write( " |