document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=200405>Question 200405</A>: <I><SPAN STYLE=\"word-break: break-all;\"> sue can shovel snow from her driveway in 40 minutes.  Jim can do the same job in 50 minutes.  How long would it take Sue and Jim to shoved the driveway if they worked together? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #150689 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=150689\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> sue can shovel snow from her driveway in 40 minutes. Jim can do the same job in 50 minutes. How long would it take Sue and Jim to shoved the driveway if they worked together?<BR>\n" );
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document.write( "In one minute, Sue shovels 1/40.<BR>\n" );
document.write( "In one minute, Jim shovels 1/50.<BR>\n" );
document.write( "Together, they to 1/40 + 1/50 per minute.<BR>\n" );
document.write( "1/40 + 1/50 = 9/200 of the drive per minute.<BR>\n" );
document.write( "The minutes per driveway = 200/9 <BR>\n" );
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document.write( "A quicker way to do these is the product/sum<BR>\n" );
document.write( "40*50/(40+50) = 2000/90 = 200/9<BR>\n" );
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