document.write( "Question 200410: Keiko bicycles 4 km/h faster than javier. In the same time it takes Javier to bicycle 30 km, Keiki can bicycle 42 jm. How fast does each bicyclist travel?\r
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document.write( "javier travel ?
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document.write( "Keiko travels ? \n" );
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Algebra.Com's Answer #150677 by RAY100(1637)![]() ![]() ![]() You can put this solution on YOUR website! Let K = velocity of Keiko,,,,,,,Let J = velocity of Javier ( km/hr),,,,Let t = time (hrs) \n" ); document.write( ". \n" ); document.write( "K= J + 4 \n" ); document.write( ". \n" ); document.write( "J=30 /t,,,,,,,K=42/t \n" ); document.write( ". \n" ); document.write( "42/t = 30/t +4,,,,,,,,,, (substitute into (1) ) \n" ); document.write( ". \n" ); document.write( "42 = 30 +4t,,,,,,,,,,,,,,,( multiply thru by t) \n" ); document.write( ". \n" ); document.write( "12 = 4t \n" ); document.write( ". \n" ); document.write( "t = 3 hrs \n" ); document.write( ". \n" ); document.write( "J=30 /3 =10 km / hr,,,,,,,,,K=42 /3 =14 km/hr,,,,,ANSWER \n" ); document.write( ". \n" ); document.write( "checking in (1) 14 = 10 +4,,,,,ok \n" ); document.write( " |