document.write( "Question 200410: Keiko bicycles 4 km/h faster than javier. In the same time it takes Javier to bicycle 30 km, Keiki can bicycle 42 jm. How fast does each bicyclist travel?\r
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document.write( "javier travel ?
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document.write( "Keiko travels ? \n" );
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Algebra.Com's Answer #150676 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! Keiko bicycles 4 km/h faster than javier. \n" ); document.write( "In the same time it takes Javier to bicycle 30 km, Keiki can bicycle 42 km. \n" ); document.write( " How fast does each bicyclist travel? \n" ); document.write( "; \n" ); document.write( "Let s = j's speed \n" ); document.write( "then \n" ); document.write( "(s+4) = k's speed \n" ); document.write( ": \n" ); document.write( "Write a time equation, Time = \n" ); document.write( ": \n" ); document.write( "k's time = j's time \n" ); document.write( " \n" ); document.write( "Cross multiply \n" ); document.write( "42s = 30(s+4) \n" ); document.write( "42s = 30s + 120 \n" ); document.write( "42x - 30s = 120 \n" ); document.write( "12s = 120 \n" ); document.write( " s = \n" ); document.write( " s = 10 km/hr is j's speed \n" ); document.write( "and \n" ); document.write( "10 + 4 = 14 km/hr is k' speed \n" ); document.write( ": \n" ); document.write( "; \n" ); document.write( "Check solution by finding the times: \n" ); document.write( "42/14 = 3 hrs \n" ); document.write( "30/10 = 3 hrs, confirms our solutions \n" ); document.write( " |