document.write( "Question 200410: Keiko bicycles 4 km/h faster than javier. In the same time it takes Javier to bicycle 30 km, Keiki can bicycle 42 jm. How fast does each bicyclist travel?\r
\n" ); document.write( "\n" ); document.write( "javier travel ?
\n" ); document.write( "Keiko travels ?
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Algebra.Com's Answer #150676 by ankor@dixie-net.com(22740)\"\" \"About 
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Keiko bicycles 4 km/h faster than javier.
\n" ); document.write( "In the same time it takes Javier to bicycle 30 km, Keiki can bicycle 42 km.
\n" ); document.write( " How fast does each bicyclist travel?
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\n" ); document.write( "Let s = j's speed
\n" ); document.write( "then
\n" ); document.write( "(s+4) = k's speed
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\n" ); document.write( "Write a time equation, Time = \"dist%2Fspeed\"
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\n" ); document.write( "k's time = j's time
\n" ); document.write( "\"42%2F%28%28s%2B4%29%29\" = \"30%2Fs\"
\n" ); document.write( "Cross multiply
\n" ); document.write( "42s = 30(s+4)
\n" ); document.write( "42s = 30s + 120
\n" ); document.write( "42x - 30s = 120
\n" ); document.write( "12s = 120
\n" ); document.write( " s = \"120%2F12\"
\n" ); document.write( " s = 10 km/hr is j's speed
\n" ); document.write( "and
\n" ); document.write( "10 + 4 = 14 km/hr is k' speed
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\n" ); document.write( "Check solution by finding the times:
\n" ); document.write( "42/14 = 3 hrs
\n" ); document.write( "30/10 = 3 hrs, confirms our solutions
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