document.write( "Question 200367: If a^(1/3)+b^(1/3)+c^(1/3)=0, then show that log[(a+b+c)/3]=1/3[loga+logb+logc] \n" ); document.write( "
Algebra.Com's Answer #150659 by orca(409)\"\" \"About 
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\"a%5E%281%2F3%29%2Bb%5E%281%2F3%29%2Bc%5E%281%2F3%29=0\"
\n" ); document.write( "\"a%5E%281%2F3%29%2Bb%5E%281%2F3%29=-c%5E%281%2F3%29\"
\n" ); document.write( "\"%28a%5E%281%2F3%29%2Bb%5E%281%2F3%29%29%5E3=%28-c%5E%281%2F3%29%29%5E3\" cube both sides
\n" ); document.write( "\"a%2B3a%5E%282%2F3%29b%5E%281%2F3%29%2B3a%5E%281%2F3%29b%5E%282%2F3%29%2Bb=-c\"
\n" ); document.write( "\"a%2Bb%2B3a%5E%281%2F3%29b%5E%281%2F3%29%28a%5E%281%2F3%29%2Bb%5E%281%2F3%29%29=-c\"
\n" ); document.write( "\"a%2Bb%2Bc%2B3a%5E%281%2F3%29b%5E%281%2F3%29%28a%5E%281%2F3%29%2Bb%5E%281%2F3%29%29=0\"
\n" ); document.write( "Noting that \"a%5E%281%2F3%29%2Bb%5E%281%2F3%29=-c%5E%281%2F3%29\", we have
\n" ); document.write( "\"a%2Bb%2Bc%2B3a%5E%281%2F3%29b%5E%281%2F3%29%28-c%5E%281%2F3%29%29=0\"
\n" ); document.write( "\"a%2Bb%2Bc=3a%5E%281%2F3%29b%5E%281%2F3%29c%5E%281%2F3%29\"
\n" ); document.write( "\"%28a%2Bb%2Bc%29%2F3=a%5E%281%2F3%29b%5E%281%2F3%29c%5E%281%2F3%29\"
\n" ); document.write( "So
\n" ); document.write( "log[(a+b+c)/3]=1/3[loga+logb+logc]
\n" ); document.write( "
\n" );