document.write( "Question 200358: HI everyone, Im trying to finish the following problems but I am struggling a bit. I have to show full working and comment on the outcomes. I dont expect answers to all 3, but if someone can show me one of each type that would be super.
\n" ); document.write( "Question 1. Find the equation of the line that passes through the point (-2,5) and parallel to the y axis.
\n" ); document.write( "Question 2. Find the equation of the line passing through (1,3) and parallel to the line y = 3/2 x - 1/2.
\n" ); document.write( "Question 3. A line with the gradient passes through the point (1,3). Find the equation of the line.\r
\n" ); document.write( "\n" ); document.write( "Thanks for your help. -Nick.
\n" ); document.write( "

Algebra.Com's Answer #150653 by nerdybill(7384)\"\" \"About 
You can put this solution on YOUR website!
Question 1. Find the equation of the line that passes through the point (-2,5) and parallel to the y axis.
\n" ); document.write( "x = -2
\n" ); document.write( ".
\n" ); document.write( "Question 2. Find the equation of the line passing through (1,3) and parallel to the line y = 3/2 x - 1/2.
\n" ); document.write( "If a two lines are parallel, the slopes are the same.
\n" ); document.write( "Our line has a slope of 3/2 crossing (1,3)
\n" ); document.write( "plug into point-slope form
\n" ); document.write( "y-y1 = m(x-x1)
\n" ); document.write( "y-3 = (3/2)(x-1)
\n" ); document.write( "y-3 = (3/2)x - 3/2
\n" ); document.write( "y = (3/2)x - 3/2 + 3
\n" ); document.write( "y = (3/2)x - 3/2 + 6/2
\n" ); document.write( "y = (3/2)x + 3/2
\n" ); document.write( ".
\n" ); document.write( "Question 3. A line with the gradient 2 passes through the point (1,3). Find the equation of the line.
\n" ); document.write( "Gradient is equivalent to the slope
\n" ); document.write( "So m = 2 and it crosses (1,3)
\n" ); document.write( "plug into point-slope form
\n" ); document.write( "y-y1 = m(x-x1)
\n" ); document.write( "y-3 = 2(x-1)
\n" ); document.write( "y-3 = 2x-2
\n" ); document.write( "y = 2x + 1
\n" ); document.write( "
\n" ); document.write( "
\n" );