document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=27688>Question 27688</A>: <I><SPAN STYLE=\"word-break: break-all;\"> In Slippery Creek, Janna can row 50 km downstream in 5 hours or she can row 25 km upstream in the same amount of time.   Find the rate she rows in still water.<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #15064 by </B><A HREF=/tutors/aboutme.mpl?userid=longjonsilver><B>longjonsilver(2297)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=longjonsilver><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=longjonsilver><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=15064\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let speed in still water = x km/hr<BR>\n" );
document.write( "Let speed of river = y km/hr\r<BR>\n" );
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document.write( "speed with river is x+y<BR>\n" );
document.write( "speed against river is x-y\r<BR>\n" );
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document.write( "with river:<BR>\n" );
document.write( "x+y = 50/5<BR>\n" );
document.write( "x+y = 10\r<BR>\n" );
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document.write( "against river:<BR>\n" );
document.write( "x-y = 25/5<BR>\n" );
document.write( "x-y = 5\r<BR>\n" );
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document.write( "so, add the 2 equations together: 2x = 15 --> x = 7.5 km/hr<BR>\n" );
document.write( "and therefore from x+y=10, y = 2.5 km/hr\r<BR>\n" );
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document.write( "jon.<BR>\n" );
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