document.write( "Question 200271: Find two consecutive odd integers such that the square of the first added to 3 times the second is 24.\r
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document.write( "n^2+3(n)=24 This is the equation I came up with \n" );
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Algebra.Com's Answer #150605 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! n^2+3(n)=24 \n" ); document.write( "n^2+3n-24=0 \n" ); document.write( " \n" ); document.write( "x=(-3+-sqrt[3^2-4*1*-24])/2*1 \n" ); document.write( "x=(-3+-sqrt[9+96])/2 \n" ); document.write( "x=(-3+-sqrt105)/2 \n" ); document.write( "x=(-3+-10.247)/2 \n" ); document.write( "x=(-3+10.247)/2 \n" ); document.write( "x=7.247/2 \n" ); document.write( "x=3.6235 ans. \n" ); document.write( "x=(-2-10.247)/2 \n" ); document.write( "x=-12.247/2 \n" ); document.write( "x=-6.1235 ans. \n" ); document.write( " |