document.write( "Question 200271: Find two consecutive odd integers such that the square of the first added to 3 times the second is 24.\r
\n" ); document.write( "\n" ); document.write( "n^2+3(n)=24 This is the equation I came up with
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Algebra.Com's Answer #150605 by checkley77(12844)\"\" \"About 
You can put this solution on YOUR website!
n^2+3(n)=24
\n" ); document.write( "n^2+3n-24=0
\n" ); document.write( "\"x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+\"
\n" ); document.write( "x=(-3+-sqrt[3^2-4*1*-24])/2*1
\n" ); document.write( "x=(-3+-sqrt[9+96])/2
\n" ); document.write( "x=(-3+-sqrt105)/2
\n" ); document.write( "x=(-3+-10.247)/2
\n" ); document.write( "x=(-3+10.247)/2
\n" ); document.write( "x=7.247/2
\n" ); document.write( "x=3.6235 ans.
\n" ); document.write( "x=(-2-10.247)/2
\n" ); document.write( "x=-12.247/2
\n" ); document.write( "x=-6.1235 ans.
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