document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=200302>Question 200302</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The length of a rectangle is  more than twice its width, and the area of the rectangle is  77 square meters. Find the dimensions of the rectangle.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #150589 by </B><A HREF=/tutors/aboutme.mpl?userid=RAY100><B>RAY100(1637)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=RAY100><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=150589\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Area + Length * Width = w* (>2w) = 77<BR>\n" );
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document.write( " 2w^2 <77<BR>\n" );
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document.write( "w^2 < 77/2 < 38.5<BR>\n" );
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document.write( "w^2 < 38.5<BR>\n" );
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document.write( "w< 6.2 m<BR>\n" );
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document.write( "L > 2w,,, L> 12.4<BR>\n" );
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document.write( "check ,,,,Area = L*W = 12.4 * 6.2 = 77,,,,ok<BR>\n" );
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document.write( "Reviewing  problem,,,Let  w  = 6.2,,,,then  L > 12.4,,,,,,satisfies  requirements </SPAN>\n" );
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