document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=200303>Question 200303</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The length of a rectangle is 3m more than twice its width, and the area of the rectangle is 77 square meters. Find the dimensions of the rectangle.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #150588 by </B><A HREF=/tutors/aboutme.mpl?userid=RAY100><B>RAY100(1637)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=RAY100><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=150588\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Area  =  Length * Width = (2w+3) * (w) = 77<BR>\n" );
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document.write( "2w^2 +3w -77 = 0<BR>\n" );
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document.write( "(2w-11)(w+7) =0<BR>\n" );
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document.write( "2w-11 = 0,,,,w=11/2=5.5 m<BR>\n" );
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document.write( "w+7 =0,,,,,,,,w=-7  (not  reasonable)<BR>\n" );
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document.write( "L= 2w+3 = 14 m<BR>\n" );
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document.write( "check,,,,,A = L*W = 14*5.5= 77,,,,ok </SPAN>\n" );
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