document.write( "Question 200310: 1) 50 – 12 + (5 – 12)2 =
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document.write( " 2)10 – 3( 5 – 9)2 – 2(3 – 5)3 =
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Algebra.Com's Answer #150581 by RAY100(1637)![]() ![]() ![]() You can put this solution on YOUR website! Remember the order of operations,,,P E M D A S,,,Parenthesis,,,Exponents,,,Multiply/Divide, left to right,,,,,,,Add / Subtract, left to right \n" ); document.write( ". \n" ); document.write( "(1) 50 -12 +(5-12) \n" ); document.write( ". \n" ); document.write( "50 -12 +( -7) \n" ); document.write( ". \n" ); document.write( "50-12 -7 \n" ); document.write( ". \n" ); document.write( "38-7 \n" ); document.write( ". \n" ); document.write( "31 \n" ); document.write( ". \n" ); document.write( "(2) 10 -3(5-9) 2 - 2(3-5)3 \n" ); document.write( ". \n" ); document.write( "10-3(-4)2 - 2(-2)3 \n" ); document.write( ". \n" ); document.write( "10-(-12)2 -(-4)3 \n" ); document.write( ". \n" ); document.write( "10 - (-24) -(-12) \n" ); document.write( ". \n" ); document.write( "10 +24 +12 \n" ); document.write( ". \n" ); document.write( "34 +12 \n" ); document.write( ". \n" ); document.write( "46 \n" ); document.write( " |