document.write( "Question 200265: Hi!\r
\n" ); document.write( "\n" ); document.write( "A biologist has two brine solutions, one containing 1% salt and another containing 4% salt. How many milliliters of each solution should he mix to obtain 1 L of a solution that contains 2.8% salt?\r
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Algebra.Com's Answer #150578 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
Let \r
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\n" ); document.write( "\n" ); document.write( "x = amount of brine solution with 1% salt (in liters)
\n" ); document.write( "y = amount of brine solution with 4% salt (in liters)\r
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\n" ); document.write( "\n" ); document.write( "Since he's mixing the two solutions to get one liter, this means that \"x%2By=1\". In other words, the two solutions add up to one liter.\r
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\n" ); document.write( "\n" ); document.write( "So the first equation is \"x%2By=1\"\r
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\n" ); document.write( "\n" ); document.write( "Since \"x\" is the amount of the 1% solution, this means that \"0.01x\" is the amount of pure salt (since 1% of the given solution is given to be salt). Also, \"0.04y\" is the amount of pure salt (from the other solution). These figures add up to the total \"0.028%28x%2By%29\" (note: 0.028 is the percentage while x+y is the total amount). Now add up the two parts and set them equal to the last portion to get \"0.01x%2B0.04y=0.028%28x%2By%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"0.01x%2B0.04y=0.028%28x%2By%29\" Start with the given equation.\r
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\n" ); document.write( "\n" ); document.write( "\"0.01x%2B0.04y=0.028x%2B0.028y\" Distribute\r
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\n" ); document.write( "\n" ); document.write( "\"10x%2B40y=28x%2B28y\" Multiply EVERY number by 1000 (to move the decimal 3 spots to the right)\r
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\n" ); document.write( "\n" ); document.write( "\"10x%2B40y-28x-28y=0\" Get everything to one side\r
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\n" ); document.write( "\n" ); document.write( "\"-18x%2B12y=0\" Combine like terms.\r
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\n" ); document.write( "\n" ); document.write( "So the second equation is \"-18x%2B12y=0\"\r
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\n" ); document.write( "\n" ); document.write( "So we have the system of equations:\r
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\n" ); document.write( "\n" ); document.write( "\"system%28x%2By=1%2C-18x%2B12y=0%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"18%28x%2By%29=18%281%29\" Multiply the both sides of the first equation by 18.\r
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\n" ); document.write( "\n" ); document.write( "\"18x%2B18y=18\" Distribute and multiply.\r
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\n" ); document.write( "\n" ); document.write( "So we have the new system of equations:\r
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\n" ); document.write( "\n" ); document.write( "\"system%2818x%2B18y=18%2C-18x%2B12y=0%29\"\r
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\n" ); document.write( "\n" ); document.write( "Now add the equations together. You can do this by simply adding the two left sides and the two right sides separately like this:\r
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\n" ); document.write( "\n" ); document.write( "\"%2818x%2B18y%29%2B%28-18x%2B12y%29=%2818%29%2B%280%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"%2818x%2B-18x%29%2B%2818y%2B12y%29=18%2B0\" Group like terms.\r
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\n" ); document.write( "\n" ); document.write( "\"0x%2B30y=18\" Combine like terms.\r
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\n" ); document.write( "\n" ); document.write( "\"30y=18\" Simplify.\r
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\n" ); document.write( "\n" ); document.write( "\"y=%2818%29%2F%2830%29\" Divide both sides by \"30\" to isolate \"y\".\r
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\n" ); document.write( "\n" ); document.write( "\"y=3%2F5\" Reduce.\r
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\n" ); document.write( "\n" ); document.write( "\"18x%2B18y=18\" Now go back to the first equation.\r
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\n" ); document.write( "\n" ); document.write( "\"18x%2B18%283%2F5%29=18\" Plug in \"y=3%2F5\".\r
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\n" ); document.write( "\n" ); document.write( "\"18x%2B54%2F5=18\" Multiply.\r
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\n" ); document.write( "\n" ); document.write( "\"5%2818x%2B54%2Fcross%285%29%29=5%2818%29\" Multiply both sides by the LCD \"5\" to clear any fractions.\r
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\n" ); document.write( "\n" ); document.write( "\"90x%2B54=90\" Distribute and multiply.\r
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\n" ); document.write( "\n" ); document.write( "\"90x=90-54\" Subtract 54 from both sides.\r
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\n" ); document.write( "\n" ); document.write( "\"90x=36\" Combine like terms.\r
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\n" ); document.write( "\n" ); document.write( "\"x=36%2F90\" Divide both sides by \"54\" to isolate \"x\".\r
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\n" ); document.write( "\n" ); document.write( "\"x=2%2F5\" Reduce.\r
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\n" ); document.write( "\n" ); document.write( "So the solutions are \"x=2%2F5\" and \"y=3%2F5\".\r
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\n" ); document.write( "\n" ); document.write( "Which form the ordered pair .\r
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\n" ); document.write( "\n" ); document.write( "These solutions in decimal form are \"x=0.4\" and \"y=0.6\"\r
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\n" ); document.write( "\n" ); document.write( "Now recall that we stated that the values of \"x\" and \"y\" are in units of liters. So this means that x=0.4 liters and y=0.6 liters\r
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\n" ); document.write( "\n" ); document.write( "Multiply both values by 1000 to convert to milliliters: 1000*0.4=400, 1000*0.6=600\r
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\n" ); document.write( "\n" ); document.write( "Answer:\r
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\n" ); document.write( "\n" ); document.write( "So this means that 400 milliliters of the 1% salt solution and 600 milliliters of the 4% salt solution are needed to make a 1 L solution that is 2.8% salt.
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