document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=200257>Question 200257</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A chemist has prepared two acid solutions, one of which is 4% acid by volume, another 11% acid.  How many cubic centimeters of each should the chemist mix together to obtain 50cm3 of 6.24% solution? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #150559 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=150559\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> .11x+.04(50-x)=.0624*50<BR>\n" );
document.write( ".11x+2-.04x=3.12<BR>\n" );
document.write( ".07x=3.12-2<BR>\n" );
document.write( ".07x=1.12<BR>\n" );
document.write( "x=1.12/.07<BR>\n" );
document.write( "x=16 cm of 11% solution.<BR>\n" );
document.write( "50-16=34 cm of 4% solution.<BR>\n" );
document.write( "Proof:<BR>\n" );
document.write( ".11*16+.04*34=3.12<BR>\n" );
document.write( "1.76+1.36=3.12<BR>\n" );
document.write( "3.12=3.12<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );