document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=27663>Question 27663</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Perform the indicated divisions.\r<BR>\n" );
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document.write( "8x^3 - 6x^2 + 2x<BR>\n" );
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document.write( "     4x + 1\r<BR>\n" );
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document.write( "I am no good at this.\r<BR>\n" );
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document.write( "I appreciate your help.  Thank you. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #15050 by </B><A HREF=/tutors/aboutme.mpl?userid=longjonsilver><B>longjonsilver(2297)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=longjonsilver><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=longjonsilver><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=15050\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> ok... long division:\r<BR>\n" );
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document.write( "in dividing 2345 by 18, you consider how many 18's go into \"2\"-000: Answer none.\r<BR>\n" );
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document.write( "Now, we extend to think of as \"23\"-00<BR>\n" );
document.write( "--> 18's in 23? answer 1 with 5 left over.\r<BR>\n" );
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document.write( "So, now how many 18's go into 545. <BR>\n" );
document.write( "--> How many 18's into 5? Answer: zero\r<BR>\n" );
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document.write( "Now we extend again<BR>\n" );
document.write( "--> how many 18's into 54? answer 3 with no remainder.\r<BR>\n" );
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document.write( "And the final 5? that is the final remainder.<BR>\n" );
document.write( "--> Complete Answer is 103 and 5/18\r<BR>\n" );
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document.write( "We do the exact same process with algebraic expressions.\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+%288x%5E3+-+6x%5E2+%2B+2x%29%2F%284x+-+1%29 ALIGN=MIDDLE  ALT=\"+%288x%5E3+-+6x%5E2+%2B+2x%29%2F%284x+-+1%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+%284x+-+1%29%7C%288x%5E3+-+6x%5E2+%2B+2x%29 ALIGN=MIDDLE  ALT=\"+%284x+-+1%29%7C%288x%5E3+-+6x%5E2+%2B+2x%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "How many 4x's go into <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=8x%5E3 ALIGN=MIDDLE  ALT=\"8x%5E3\"   DISABLED_style= \"max-width:90%; height:auto;\" >? Answer is <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2x%5E2 ALIGN=MIDDLE  ALT=\"2x%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" >.\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2x%5E2+%2A+%284x-1%29 ALIGN=MIDDLE  ALT=\"2x%5E2+%2A+%284x-1%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > is <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%288x%5E3-2x%5E2%29 ALIGN=MIDDLE  ALT=\"%288x%5E3-2x%5E2%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > so subtract that from the original, leaving us with <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%28-4x%5E2%2B2x%29 ALIGN=MIDDLE  ALT=\"%28-4x%5E2%2B2x%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > --> call this the \"new original\"\r<BR>\n" );
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document.write( "Now repeat the process...<BR>\n" );
document.write( "How many times does 4x go into <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%28-4x%5E2%29 ALIGN=MIDDLE  ALT=\"%28-4x%5E2%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "Answer is -x.\r<BR>\n" );
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document.write( "So, <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%28-x%29%2A%284x-1%29 ALIGN=MIDDLE  ALT=\"%28-x%29%2A%284x-1%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > is <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=-4x%5E2%2Bx ALIGN=MIDDLE  ALT=\"-4x%5E2%2Bx\"   DISABLED_style= \"max-width:90%; height:auto;\" >. Now subtract that from the \"new original\", leaving us with x --> call this the \"new original\".\r<BR>\n" );
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document.write( "Now repeat the process again...<BR>\n" );
document.write( "How many times does 4x go into x<BR>\n" );
document.write( "Answer is (1/4).\r<BR>\n" );
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document.write( "So <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%281%2F4%29%2A%284x-1%29 ALIGN=MIDDLE  ALT=\"%281%2F4%29%2A%284x-1%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > is <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x-%281%2F4%29 ALIGN=MIDDLE  ALT=\"x-%281%2F4%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >. Now subtract this from the \"new original\", leaving us with (1/4).\r<BR>\n" );
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document.write( "This is the end.<BR>\n" );
document.write( "Answer to <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+%288x%5E3+-+6x%5E2+%2B+2x%29%2F%284x+-+1%29 ALIGN=MIDDLE  ALT=\"+%288x%5E3+-+6x%5E2+%2B+2x%29%2F%284x+-+1%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > is <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2x%5E2-x%2B%281%2F4%29 ALIGN=MIDDLE  ALT=\"2x%5E2-x%2B%281%2F4%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > with remainder (1/4).\r<BR>\n" );
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document.write( "The secret is to put the working out under itself, in neat columns, so you can see it all. I cannot do that here :-( However, this website \r<BR>\n" );
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document.write( "http://www.rfbarrow.btinternet.co.uk/htmasa2/AlgDiv1.htm\r<BR>\n" );
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document.write( "shows the process perfectly.\r<BR>\n" );
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document.write( "jon.\r<BR>\n" );
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