document.write( "Question 200181: A certain sum of money is invested at 10%. Twice that amount is invested at 8%. The total amount of interest from both investments is 91 dollars. How much is invested at 8%.
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Algebra.Com's Answer #150482 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! .10x+.08*2x=91 \n" ); document.write( ".10x+.16x=91 \n" ); document.write( ".26x=91 \n" ); document.write( "x=91/.26 \n" ); document.write( "x=$350 is the amount invested @ 10% \n" ); document.write( "2*350=$700 is the amount invested @ 8% \n" ); document.write( "Proof: \n" ); document.write( ".10*350+.08*700=91 \n" ); document.write( "35+56=91 \n" ); document.write( "91=91 \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |