document.write( "Question 200181: A certain sum of money is invested at 10%. Twice that amount is invested at 8%. The total amount of interest from both investments is 91 dollars. How much is invested at 8%.
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Algebra.Com's Answer #150482 by checkley77(12844)\"\" \"About 
You can put this solution on YOUR website!
.10x+.08*2x=91
\n" ); document.write( ".10x+.16x=91
\n" ); document.write( ".26x=91
\n" ); document.write( "x=91/.26
\n" ); document.write( "x=$350 is the amount invested @ 10%
\n" ); document.write( "2*350=$700 is the amount invested @ 8%
\n" ); document.write( "Proof:
\n" ); document.write( ".10*350+.08*700=91
\n" ); document.write( "35+56=91
\n" ); document.write( "91=91
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